The numbers are 105 and 50
<em><u>Solution:</u></em>
Let "x" be the first number
Let "y' be the second number
Twice a number plus twice a second number is 310
Therefore,
twice of x + twice of y = 310
2x + 2y = 310 ---------- eqn 1
The difference between the numbers is 55
x - y = 55 -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 2,
x = 55 + y ------ eqn 3
<em><u>Substitute eqn 3 in eqn 1</u></em>
2(55 + y) + 2y = 310
110 + 2y + 2y = 310
4y = 310 - 110
4y = 200
<h3>y = 50</h3>
<em><u>Substitute y = 50 in eqn 3</u></em>
x = 55 + 50
<h3>x = 105</h3>
Thus the numbers are 105 and 50
Set up a proportion
3 coins:8 notes and then the other one 24 coins : x (unknown notes)
they have a relationship so we can set them equal to each other.
3/8=24/x cross multiply: 8 * 24 = 192
Now divide that by 3: 192/3 = 64
So there are 64 notes in the bag
Answer:
Step-by-step explanation:
• 
Let's use FOIL (first, outer, inner, last) to solve this. We'll multiply the terms by one another in that fashion.
Rearrange in decreasing exponents.
