The area of a trapezoid is basically the average width times the altitude, or as a formula:
Area = h ·
b 1 + b 2
2
where
b1, b2 are the lengths of each base
h is the altitude (height)
Recall that the bases are the two parallel sides of the trapezoid. The altitude (or height) of a trapezoid is the perpendicular distance between the two bases.
In the applet above, click on "freeze dimensions". As you drag any vertex, you will see that the trapezoid redraws itself keeping the height and bases constant. Notice how the area does not change in the displayed formula. The area depends only on the height and base lengths, so as you can see, there are many trapezoids with a given set of dimensions which all have the same area.
Answer:
option A)
(40, 96)
Step-by-step explanation:
Given that,
The coordinates of point K and J are
K(160,120)
J(-40,80)
x1 = 160
x2 = -40
y1 = 120
y2 = 80
P is (3/5) the line of the line segment from K to J
So, KP = (3/5) KJ and JP = (2/5) KJ
OR we will divide the length of KJ with the ratio 3 : 2 from K
m : n
3 : 2
m = 3
n = 2
by using this formula and putting values in it
xp = (m/m+n)(x2-x1) + x1
yp = (m/m+n)(y2-y1) + y1
xp = (3/3+2) (-40-160) + 160
yp = (3/3+2) (80-120) + 120
xp = 40
yp = 96
Well it's gonna be 28 because it just isn't it
So try try again
Hello from MrBillDoesMath!
Answer:
4( x + 1.5)^2 + 0
Discussion:
4x^2 + 12x + 9 = => factor "4" from first 2 terms
4 (x^2 + 3x) + 9 = => complete the square, add\subtract (1.5)^2
4(x^2 + 3x + (1.5)^2) - 4 (1.5)^2 + 9 =
4 ( x + 1.5)^2 + ( 9 - 4(1.5)^2) = => as (1.5)^2 = 2.25
4 ( x + 1.5)^2 + ( 9 - 4(2.25)) = => as 4 ( 2.25) = 9
4 ( x+ 1.5)^2 + 0
Thank you,
MrB
First convert 6 feet to inches.
12x6=72
Then write a proportion!
8/72=4/x
Cross multiply!
72x4=8 x x
288=8x
Divide by 8 on both sides.
x=36 inches. or 3 feet
Answer is 3 feet or 36 inches