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Andreyy89
3 years ago
10

What are the chances of flipping a coin 12 times and it landing on heads 11 times?

Mathematics
1 answer:
lubasha [3.4K]3 years ago
8 0
12 flips, 11 heads, 1 tails
Let's say there's a 50-50 chance of landing heads.
There are 12 flips and 12 specific outcomes.
The probability is 2^(-12) = 1/4096 = 0.0244%

If the last flip doesn't matter, then the probability would be 2^(-11) = 1/2048 = 0.0488%.

Have an awesome day! :)

From your friendly Helper-in-Training, collinjun0827
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If EG = 59, and EF = 8x - 14, while FG = 4x + 1
lyudmila [28]

Answer:

x = 6

Step-by-step explanation:

EG = 59

EF = 8x - 14

FG = 4x + 1

to find the value of x

EF + FG = EG (same line)

8x - 14 + 4x + 1 = 59

12x -13 = 59

12x = 59 + 13

12x = 72

x = 72 ÷ 12

x = 6

You can even cross check for correct answer

EF + FG = EG

instead of x place the x's value we got

8x - 14 + 4x + 1 = 59

8 (6) - 14 + 4 (6) + 1 = 59

48 - 14 + 24 + 1 = 59

34 + 25 = 59

59 = 59

CROSS - CHECKED

4 0
2 years ago
Calculate the straight line distance between the points (-10, -7) and (-8,1).<br> G.2(B)
tia_tia [17]

Answer:

2√(17) or about 8.2462 units.

Step-by-step explanation:

We want to determine the distance between the two points (-10, -7) and (-8, 1).

We can use the distance formula. Recall that:

\displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Substitute and evaluate:

\displaystyle \begin{aligned} d &= \sqrt{((-10)-(-8))^2 + ((-7) - (1))^2} \\ \\ &=\sqrt{(-2)^2+(-8)^2} \\ \\ &= \sqrt{(4) + (64)} \\ \\ &= \sqrt{68}\\ \\ &= 2\sqrt{17}\end{aligned}

Hence, the distance between (-10, -7) and (-8, 1) is 2√(17) units or about 8.2462 units.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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