Answer:
u=95
Step-by-step explanation:
To solve this problem we need to isolate 'u' variable using properties of equation.
Lets multiply by -9 the whole equation
u - -23=-8*9
Remember keys features of algebra:
- * - = +
- * += -
+ * - = -
+ * + =+
So, our equations becomes>
u+23=-72
Lets now subtract 23 to both sides
u-23=-72-23
We have u=95
1) 13a=-5
Make a the subject of the formula by dividing both sides by 13(the coefficient of a)
13a/13=-5/13
Therefore a= -0.385
The second one). 12-b= 12.5
You take the 12 to the other side making b subject of the formula (-b in this case)
-b= 12.5-12
-b= 0.5
(You cannot leave b with a negative sign so you will divide both sides by -1 to cancel out the negative sign)
-b/-1= 0.5/-1
Therefore b=-0.5
The third one). -0.1= -10c
You will divide both sides by the coefficient of c(number next to c) which is -10
-0.1/-10= -10c/-10
Hence, c= 0.01
A(b)+16 = 16 larger than the product of a and b.
We have to calculate the probability of picking a 4 and then a 5 without replacement.
We can express this as the product of the probabilities of two events:
• The probability of picking a 4
,
• The probability of picking a 5, given that a 4 has been retired from the deck.
We have one card in the deck out of fouor cards that is a "4".
Then, the probability of picking a "4" will be:
The probability of picking a "5" will be now equal to one card (the number of 5's in the deck) divided by the number of remaining cards (3 cards):
We then calculate the probabilities of this two events happening in sequence as:
Answer: 1/12
