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3 years ago

Explain (1+y)^2 how does it turn into 1+2y+y^2 ? i don't understand

1 answer:

6 0

I will show you the steps on how you get that answer and if you have any questions after that let me know and I'd be more than happy to help answer them for you.
The first step for solving (1 + y)² is to use the equation (a + b)² = a² + 2ab + b² to expand the expression.
1² + 2 × 1y + y²
1 raised to any power equals 1,, so remove the power.
1 + 2 × 1y + y²
Calculate the product of 2 × 1y.
1 + 2y + y²
Finally,, use the commutative property to reorder the terms.
y² + 2y + 1
Let me know if you have any further questions.
:)

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Graph g is a translation of the graph of y= sin x (dashed line).a) write down the equation of g b) write down the coordinates of

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Answer:

a) $G(x)= \sin x + 2$

b) The coordinates of P are

$\displaystyle \left( \frac{3\pi}{2},1\right)$

Step-by-step explanation:

Translation

The dashed line shows the graph of the function

$y = \sin x$

This function has a maximum value of 1, a minimum value of -1, and a center value of 0.

Graph G shows the same function but translated by 2 units up, thus the equation of G is:

$\boxed{G(x)= \sin x + 2}$

b) The coordinates of P correspond to the value of

$x = \frac{3\pi}{2}$

The value of G is

$\displaystyle G(\frac{3\pi}{2})= \sin \frac{3\pi}{2} + 2$

Since

$\sin \frac{3\pi}{2}=-1$

$\displaystyle G(\frac{3\pi}{2})= -1+ 2=1$

The coordinates of P are

$\displaystyle \left( \frac{3\pi}{2},1\right)$

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3 years ago

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Inessa [10]

Answer:

Step-by-step explanation:

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A sample of 1000 college students at NC State University were randomly selected for a survey. Among the survey participants, 102

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Answer:

The upper endpoint of the 99% confidence interval for population proportion is 0.13.

Step-by-step explanation:

The confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Given:

n = 1000

$\hat p$ = 0.102

$z_{\alpha /2}=z_{0.01/2}=z_{0.005}=2.58$

*Use the standard normal table for the critical value.

Compute the 99% confidence interval for population proportion as follows:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.102\pm 2.58\times\sqrt{\frac{0.102(1-0.102)}{1000}}\\=0.102\pm0.0248\\=(0.0772, 0.1268)\\\approx (0.08, 0.13)$

Thus, the upper limit of the 99% confidence interval for population proportion is 0.13.

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Answer:

False

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