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svlad2 [7]
3 years ago
9

The expression 15w + 65 factored using the gcf is?

Mathematics
2 answers:
Mrac [35]3 years ago
8 0
The gcf is 5, factored it’d look like
5(w+13)
astraxan [27]3 years ago
4 0

Answer:

5(3w+13)

Step-by-step explanation:

1) Prime factorization of 65 and 15 will give us 5 as is Greatest Common Factor

65|5

13|13

1

15|5

3|3

1

2

2) Placing the common factor outside the parentheses. And inside the sum of its quotients.

\frac{65}{5}=13\\\frac{15w}{5}=3w\\

There you have, a simplified expression:

5(3w+13)

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What’s the answer to -3 + 47 = 5x + 103
Solnce55 [7]

Answer:

-11.8

Step-by-step explanation:

hope this helps!!!:)

6 0
3 years ago
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What is the solution of <br> x/2=6
Lina20 [59]

Answer:

12

Step-by-step explanation:

12/2=6

replace x with 12

4 0
3 years ago
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Bryan has a square parcel of land that is 120 yards long and 120 yards wide. The land is planted with Bermuda grass and surround
Mekhanik [1.2K]
The diagonal fencing will be the hypotenuse of a right triangle with sides 120yds long so:

h=√2(120^2))

h=√28800 yd

And the surrounding fencing will just be four times the side length of 120yds so:

s=480yd

So the total fencing needed is:

f=480+√28800 yards

f≈649.71 yd  (to nearest hundredth of a yard)  which is

f≈650 yds  (to nearest whole yard)

But, I wasn't sure, if they just want the diagonal fencing needed then it is just:

f=√28800

f≈170 yds  (to nearest yard)


6 0
3 years ago
Read 2 more answers
DONT ANSWER UNLESS I KNOW YOU!!!
Vsevolod [243]

Since Area equals length times width

A=L x W


And its asking twice its width

The height is 15 so if you add it its 30


So to get the answer you multiply 30 times 15 and you will get 450


Hope this helped you :D


Tobey Snaps

6 0
3 years ago
The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci
4vir4ik [10]

Answer:

(a) The confidence interval is: 0.0304 ≤ π ≤ 0.0830.

(b) Upper confidence bound = 0.0787

Step-by-step explanation:

(a) The confidence interval for p (proportion) can be calculated as

p \pm z*\sigma_{p}

\sigma=\sqrt{\frac{\pi*(1-\pi)}{N} }\approx\sqrt{\frac{p(1-p)}{N} }

NOTE: π is the proportion ot the population, but it is unknown. It can be estimated as p.

p=17/300=0.0567\\\\\sigma=\sqrt{\frac{p(1-p)}{N} }=\sqrt{\frac{0.0567(1-0.0567)}{300} }=0.0134

For a 95% two-sided confidence interval, z=±1.96, so

\\LL = p-z*\sigma=0.0567 - (1.96)(0.0134) = 0.0304\\UL =p+z*\sigma= 0.0567 + (1.96)(0.0134) = 0.0830\\\\

The confidence interval is: 0.0304 ≤ π ≤ 0.0830.

(b) The confidence interval now has only an upper limit, so z is now 1.64.

UL =p+z*\sigma= 0.0567 + (1.64)(0.0134) = 0.0787

The confidence interval is: -∞ ≤ π ≤ 0.0787.

5 0
3 years ago
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