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timofeeve [1]
3 years ago
10

PLEASE _PLEASE, ANSWER RN I NEED A ANSWER RIGHT NOW ILL GIVE U BRAINLIEST. and youll get a 100 points. if u answer.

Mathematics
2 answers:
iVinArrow [24]3 years ago
8 0

Answer:

Ima go w/ Menes

Step-by-step explanation:

zaharov [31]3 years ago
4 0

Answer:

what pharaoh built the first pyramid?

Step-by-step explanation:

A. Djoser

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Use the following cell phone airport data speeds​ (Mbps) from a particular network. Find the percentile corresponding to the dat
iren2701 [21]
2.7 2.8 3.2.3.64.5 it has to be that answer
7 0
3 years ago
What's the answer? Serious answers only please, :/.
mr Goodwill [35]

Answer:

2.5 cm

Step-by-step explanation:

Rectangle A    L x W = 40

                   

Rectangle B     L * W   = 1/2 (40)

                        8 * W = 20

                              W = 2.5 cm

5 0
2 years ago
Read 2 more answers
Dos cuadrados de lado
Kaylis [27]

La franja amarilla del rectángulo tiene un área de 30 centímetros cuadrados.

<h3>¿Cuál es el área de la franja amarilla del rectángulo?</h3>

En este problema tenemos un rectángulo formado por dos cuadrados que se traslapan uno al otro. La franja amarilla es el área en la que los cuadrados se traslapan. La anchura del rectángulo es descrita por la siguiente ecuación:

(10 - x) + 2 · x = 17

Donde x se mide en centímetros.

A continuación, despejamos x en la ecuación descrita:

10 + x = 17

x = 7

Ahora, el área de la franja amarilla se determina mediante la fórmula de area de un rectángulo:

A = b · h

Donde:

  • b - Base del rectángulo, en centímetros.
  • h - Altura del rectángulo, en centímetros.
  • A - Área del rectángulo, en centímetros cuadrados.

A = (10 - 7) · 10

A = 3 · 10

A = 30

El área de la franja amarilla del rectángulo es igual a 30 centímetros cuadrados.

Para aprender más sobre áreas de rectángulos: brainly.com/question/23058403

#SPJ1

8 0
1 year ago
For what real value of $v$ is $\frac{-21-\sqrt{301}}{10}$ a root of $5x^2+21x+v$?
Degger [83]

Answer:

v = 7

is the value for which

x = (-21 - √301)/10

is a solution to the quadratic equation

5x² + 21x + v = 0

Step-by-step explanation:

Given that

x = (-21 - √301)/10 .....................(1)

is a root of the quadratic equation

5x² + 21x + v = 0 ........................(2)

We want to find the value of v foe which the equation is true.

Consider the quadratic formula

x = [-b ± √(b² - 4av)]/2a ..................(3)

Comparing (3) with (2), notice that

b = 21

2a = 10

=> a = 10/2 = 5

and

b² - 4av = 301

=> 21² - 4(5)v = 301

-20v = 301 - 441

-20v = -140

v = -140/(-20)

v = 7

That is a = 5, b = 21, and v = 7

The equation is then

5x² + 21x + 7 = 0

6 0
3 years ago
Help Please 15 points
Tpy6a [65]

Answer:

The Answer is c: 4x5 + x3 + 2x2 – 3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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