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swat32
3 years ago
13

During 7 1/2 months of hibernation, a black bear experienced a weight loss of 64.4 pounds.

Mathematics
2 answers:
Nikitich [7]3 years ago
8 0

Answer:

8.58666666666666667...

Step-by-step explanation: You just divide 64.4 pounds by 7.5 months and you and you will get 8.5866666666666667

Yakvenalex [24]3 years ago
4 0

Answer:

8.6

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
49/10 as a mixed number
anastassius [24]
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8 0
3 years ago
In a naval engagement, one-third of the fleet was captured, one-sixth was sunk, and two ships were destroyed by fire. One-sevent
Otrada [13]

Answer:

60 ships.

Step-by-step explanation:

Let the total number of ships in the naval fleet be represented by x

One-third of the fleet was captured = 1/3x

One-sixth was sunk = 1/6x

Two ships were destroyed by fire = 2

Let surviving ships be represented by y

One-seventh of the surviving ships were lost in a storm after the battle = 1/7y

Finally, the twenty-four remaining ships sailed home

The 24 remaining ships that sailed home =

y - 1/7y = 6/7y of the surviving fleet sailed home.

Hence

24 = 6/7y

24 = 6y/7

24 × 7/ 6

y = 168/6

y = 28

Therefore, total number of ships that survived is 28.

Surviving ships lost in the storm = 1/7y = 1/7 × 28 = 4

Total number of ships in the fleet(x) =

x = 1/3x + 1/6x + 2 + 28

Collect like terms

x - (1/3x + 1/6x) = 30

x - (1/2x) = 30

1/2x = 30

x = 30 ÷ 1/2

x = 30 × 2

x = 60

Therefore, ships that were in the fleet before the engagement were 60 ships.

3 0
3 years ago
The SAT mathematics scores in the state of Florida for this year are approximately normally distributed with a mean of 500 and a
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99.7%

This is because the likelihood of a point being within 2 SDs of the mean is 99.7%. 
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