Answer:
x=4 Inch
Step-by-step explanation:
Length of the Square = 24 Inches
If a Square of Length x cm is cut out from each corner
Length of the Box = 24-x-x=(24-2x) Inches
Width of the Box =24-x-x=(24-2x) Inches
Height of the box = x inches
Volume of a Cuboid = Length X Width X Height
V(x)= x(24-2x)(24-2x)
Simplifying
V(x)=4x(12-x)(12-x)
To determine the value of x at which V is largest, we take the derivative of V(x) and solve for the critical points.
V(x)=4x(12-x)(12-x)
Set the derivative equal to zero to obtain the critical points
x cannot be equal to 12 as it divides the length of the square cardboard into exactly two equal parts.
When x=4
V(4)=4*4(12-4)(12-4)=16*8*8=1024 Cubic Inches
When x=4 Inch, the volume, V of the open box is largest.
Answer:
An =4^(n-1)
Step-by-step explanation:
hello :
the sequence is geometric because : (-64)/(-16) = (-16)/(-4)=-4/-1= 4=r
the nth term is : An =A1 × r^(n-1)
a common ratio is : r and A1 the first term
in this exercice : r =4 A1 = 1
An =A1 × r^(n-1)
An =1 × 4^(n-1)=4^(n-1)
Answer:
Natural Numbers (N), (also called positive integers, counting numbers, or natural numbers); They are the numbers {1, 2, 3, 4, 5, …} Whole Numbers (W). This is the set of natural numbers, plus zero, i.e., {0, 1, 2, 3, 4, 5, …}
Answer:
-36m + 900 < 44m + 100
Step-by-step explanation:
Given that:
The first barrel contains 900 liters of the solution; &
The second barrel contains 100 liters of solution.
So, Laura drains the first barrel at the rate of 36 liters/ min
Since Laura is draining the solution in the first barrel;
Then; we have - 36m + 900 litres
Also; Laura fills the second barrel at a rate of 44 liters per minute.
Since Laura is filling the barrel; we have: 44m + 100
Therefore; the inequality representing when the second barrel contains a greater or equal amount of solution than the first barrel can be expressed as:
- 36m + 900 < 44m + 100
Answer:
The first submarine needs to travel at a rate of [-180 – (-1,320)] ÷ 60 = 19 feet per minute.
The second submarine needs to travel at a rate of [-180 – (-1,440)] ÷ 60 = 21 feet per minute.
21 – 19 = 2, so the second submarine must travel 2 feet per minute faster than the first sub.
