121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range

The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.
The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:

So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range

That's probably the answer they're looking for.
Answer:
7
Step-by-step explanation:
Note that [ (2x)^x ]^(1/x) = 2x, and that [ (2x)^(2x) ]^(1/x) = (2x)^2 = 4x^2
Multiplying these 2 results together, we get (2x)(4x^2) = 8x^3 (answer)
The formula for slope is (y2 -- y1) / (x2 -- x1).
(0,3) (4,5)
5 - 4 = 1
3 - 0 = 3
So the slope is 1/3.
Hope this Helps!!
Answer:
3
Step-by-step explanation:
Here, by reading the histogram, we will provide answer for the question asked.
We want to know how many more festivals had 18 to 23 countries represented than 0 to 5 countries.
Checking the histogram, we can see the 0-5 countries having a value of 1, while the 18-23 has a value of 4.
So, the number of more countries will be simply 4-1 = 3