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3 years ago

What number multiplied by itself 3 times equals -64

Mathematics

1 answer:

charle [14.2K]3 years ago

7 0

-64/3 divide -64 by 3

-21.33333333333333333
or
-21 1/3

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A TV screen is 41 cm long and 31 cm high. The length of the diagonal is closest to: A) 49 cm Eliminate B) 51 cm C) 54 cm D) 48 c

GuDViN [60]

Answer:

The length of the diagonal is closest to 51 cm.

Step-by-step explanation:

Given:

TV screen is 41 cm long and 31 cm high.

Now, to find the length of the diagonal.

By using pythagorean theorem:

leg 1 = 41 cm, leg 2 = 31 cm.

Let the hypotenuse be $x$ .

(leg 1)² + (leg 2)² = hypotenuse²

$41^{2} +31^{2}=x^{2}$

⇒ $1681+961=x^{2}$

⇒ $2642=x^{2}$

Using square root on both sides we get:

⇒ $51.40=x$

So, the length of the diagonal = 51.40 cm.

By rounding off of 51.40cm it becomes 51 cm.

Therefore, the length of the diagonal is closest to 51 cm.

7 0

3 years ago

10x3 + 13x² + 13x + 9) = (x2 + x + 1)

Zielflug [23.3K]

Answer:

barbielatttt

Step-by-step explanation:

barbieelat

5 0

3 years ago

In a group of 28 students, 6 study both Art and Biology.

Helen [10]

Answer:

3/13

Step-by-step explanation:

There are 28 students. 1 studies biology but not art. 1 studies neither subject. Therefore, there are 26 students who study art.

Of the 26 students who study art, 6 also study biology. So the probability is 6/26, which reduces to 3/13.

4 0

3 years ago

Suppose that prices of a certain model of a new home are normally distributed with a mean of $150,000. Use the 68-95-99.7 rule t

levacccp [35]

Answer:

68% of buyers paid between $147,700 and $152,300.

Step-by-step explanation:

We are given that prices of a certain model of a new home are normally distributed with a mean of $150,000.

Use the 68-95-99.7 rule to find the percentage of buyers who paid between $147,700 and $152,300 if the standard deviation is $2300.

Let X = prices of a certain model of a new home

SO, X ~ Normal( $\mu=150,000 ,\sigma=2,300$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean price = $150,000

$\sigma$ = standard deviation = $2,300

Now, according to 68-95-99.7 rule;

Around 68% of the values in a normal distribution lies between $\mu-\sigma$ and $\mu-\sigma$ .

Around 95% of the values occur between $\mu-2\sigma$ and $\mu+2\sigma$ .

Around 99.7% of the values occur between $\mu-3\sigma$ and $\mu+3\sigma$ .

So, firstly we will find the z scores for both the values given;

Z = $\frac{X-\mu}{\sigma}$ = $\frac{147,700-150,000}{2,300}$ = -1

Z = $\frac{X-\mu}{\sigma}$ = $\frac{152,300-150,000}{2,300}$ = 1

This indicates that we are in the category of between $\mu-\sigma$ and $\mu-\sigma$ .

SO, this represents that percentage of buyers who paid between $147,700 and $152,300 is 68%.

7 0

3 years ago

Jemila has $10, $5, and $1 bills in her piggy bank. Their total value is $63. If she has two more $5 bills than $10 bills, and t

earnstyle [38]

Answer:

She has 3 $10 bills, 5 $5 bills and 8 $1

3 times 10= $30

5 times 5 = $25

8 times 1 = $8

$30 + $25 + $8 = $63

4 0

4 years ago

Read 2 more answers