Easy
recall that
an=a1(r)^(n-1)
so
given 2nd and 5th term
we get
a2 and a5
so
a2=a1(r)^(2-1)=a1(r)^1=a1r
a5=a1(r)^(5-1)=a1(r)^4
also remember that

so

so r^3=-64
cube root
r=-4
so
a2=a1r=-8
a2=a1(-4)=-8
divide both sides by -4
a1=2
so
equation is

C isi the answer
You’re answer should be 9-7 hope this helped
There two zero’s hopefully
Answer:
see explanation
Step-by-step explanation:
(a)
f(0)
Since x = 0 < 5, then
f(0) = x + 4 = 0 + 4 = 4
(b)
f(6)
Since x = 6 meets the condition 5 ≤ x < 7, then
f(6) = 8