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DochEvi [55]
3 years ago
10

Daniel could do 20 pushups when he first began his workout program. He increased the number of pushups he completed by 5 each we

ek for 8 wk. Let w represent the number of weeks, and let p represent the number of pushups he completed.
What is the slope of the line that models this situation?

A.
5

B.
8

C.
20

D.
40
Mathematics
2 answers:
Alja [10]3 years ago
8 0
Your answer is simply,A(5)
ZanzabumX [31]3 years ago
4 0
The answer would have to b. 
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you need 20 hours babysitting  here is how you solve that

you subtract 25 form 165 which is 140 then you divide by 7 which is 20.

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What is the area of a 3.3in circle​
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Answer:

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Step-by-step explanation:

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Im really confused can somebody explain this?
vovikov84 [41]

<u>Given</u>:

The given ratio is 16 : 12

We need to determine three ratios that are equivalent to the given ratio.

<u>Option A</u>: 8:6

The given ratio is 16 : 12

Let us divide the given ratio 16 : 12 by 2.

Thus, we have;

8:6

Hence, the expression 8:6 is equivalent to 16 : 12

Thus, Option A is the correct answer.

<u>Option B</u>: 32:24

The number 32 goes by 16 in 2 times and the number 24 goes by 12 in 2 times.

Thus, multiplying the ratio 16 : 12 by 2, we get;

32:24

Thus, the expression 32:24 is equivalent to 16 : 12

Hence, Option B is the correct answer.

<u>Option C</u>: 4:3

Let us divide the given ratio 16 : 12 by 4.

Thus, we have;

4:3

Thus, the expression 4:3 is equivalent to 16 : 12

Hence, Option C is the correct answer.

<u>Option D</u>: 12:8

The number 12 goes by 16 in \frac{3}{4} times and the number 8 goes by 12 in \frac{2}{3} times.

The ratios are multiplied by different numbers.

Thus, the expression 12:8 is not equivalent to 16 : 12

Hence, Option D is not the correct answer.

<u>Option E</u>: 24:16

The number 24 goes by 16 in 1.5 times and the number 16 goes by 12 in 0.75 times.

The ratios are multiplied by different numbers.

Thus, the expression 24:16 is not equivalent to 16 : 12

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5 0
3 years ago
Can someone help me Please
gulaghasi [49]

Answer:

6x^3+6y^3+10

Step-by-step explanation:

7 0
3 years ago
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How do you solve this equation . Q=3a+5ac
mr_godi [17]
A "solution" would be a set of three numbers ... for Q, a, and c ... that
would make the equation a true statement.

If you only have one equation, then there are an infinite number of triplets
that could do it.  For example, with the single equation in this question,
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There are infinite possibilities with one equation.

In order to have a unique solution ... three definite numbers for Q, a, and c ...
you would need three equations.
8 0
3 years ago
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