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bazaltina [42]
3 years ago
12

Graph

n="absmiddle" class="latex-formula">

Mathematics
1 answer:
AURORKA [14]3 years ago
5 0

Answer:

The graph is shown in the following image

Step-by-step explanation:

The parent function of f(x) = | x + 1 | +2  is y = | x |

The graph of y = | x | is the union of two lines:

y = x       for    x\geq0

y = -x      for    x

The vertex of this graph is in point (0,0)

<em>The graphic is shown in the attached image</em>.

Then, if we do  y = f(x + 1)   to the parent function we get:

y = | x + 1 |

This transformation shifts the graph of  y = |x|   1 unit to the left

Then, if we make the transformation  y = f(x) + 2  to the function  y = | x + 1 |   we obtain:

y = | x + 1 | +2

This transformation displaces the graph of the function   y = | x + 1 |    2 units up on the y axis.

So, if the vertex of the main function  y = | x |  was at point (0,0), the vertex of the function  f(x) = |x + 1| +2  has its vertex in the point (-1, 2).

<em>The graph is shown in the following image</em>

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Complete the factorization of 3x ^ 2 - 10x + 8 3x^ 2 -10x+8=(x- Box x-4)
aniked [119]

Answer:

3x^2-10x+8=(x-x_1)(x-x_2)=(x-2)(x-\frac{4}{3})

Step-by-step explanation:

The general form of a quadratic polynomial is given by:

ax^2+bx+c    (1)

You have the following polynomial:

3x^2-10x+8    (2)

In order to complete the factorization you can use the quadratic formula, to obtain the roost of the polynomial. The quadratic formula is given by:

x_{1,2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}    (3)

By comparing the equation (1) with the equation (2) you obtain:

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x_{1,2}=\frac{-(-10)\pm \sqrt{(-10)^2-4(3)(8)}}{2(3)}\\\\x_{1,2}=\frac{10\pm2}{6}\\\\x_1=2\\\\x_2=\frac{4}{3}

Then, the factorization of the polynomial is:

3x^2-10x+8=(x-x_1)(x-x_2)=(x-2)(x-\frac{4}{3})

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2 years ago
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Nadya [2.5K]
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Step-by-step explanation:

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