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zimovet [89]
2 years ago
8

Among 320 randomly selected airline travelers, the mean number of hours spent travelling per year is 24 hours and the standard d

eviation is 2. 9. What is the margin of error, assuming a 90% confidence level? Round your answer to the nearest tenth.
Mathematics
2 answers:
Andre45 [30]2 years ago
7 0

Answer:

.3

Greater than .3

Step-by-step explanation:

Edge 100%

Ostrovityanka [42]2 years ago
5 0

The margin of error of the random selection is 0.29

The given parameters are:

n = 320 --- the sample size

\sigma = 2.9 --- the standard deviation

\bar x = 24 --- the mean

\alpha = 90\% --- the confidence level.

The margin of error (E) is calculated as follows:

E = z \times \sqrt{\frac{\sigma^2}{n}}

So, we have:

E = z \times \sqrt{\frac{3.2^2}{320}}

E = z \times \sqrt{\frac{10.24}{320}}

The z-value for 90% confidence level is 1.645.

Substitute 1.645 for z

E = 1.645 \times \sqrt{\frac{10.24}{320}}

E = 1.645 \times \sqrt{0.032}

Take square roots

E = 1.645 \times 0.1789

Multiply

E = 0.2943

Approximate

E = 0.29

Hence, the margin of error is 0.29

Read more about margin of error at:

brainly.com/question/14396648

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Answer: (-8/5,0)

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7 0
3 years ago
17 The table shows some information about the dress sizes of 25 women.
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2 years ago
Given that m∠abc=70° and m∠bcd=110°. Is it possible (consider all cases): Line AB intersects line CD?
lyudmila [28]

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