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zimovet [89]
2 years ago
8

Among 320 randomly selected airline travelers, the mean number of hours spent travelling per year is 24 hours and the standard d

eviation is 2. 9. What is the margin of error, assuming a 90% confidence level? Round your answer to the nearest tenth.
Mathematics
2 answers:
Andre45 [30]2 years ago
7 0

Answer:

.3

Greater than .3

Step-by-step explanation:

Edge 100%

Ostrovityanka [42]2 years ago
5 0

The margin of error of the random selection is 0.29

The given parameters are:

n = 320 --- the sample size

\sigma = 2.9 --- the standard deviation

\bar x = 24 --- the mean

\alpha = 90\% --- the confidence level.

The margin of error (E) is calculated as follows:

E = z \times \sqrt{\frac{\sigma^2}{n}}

So, we have:

E = z \times \sqrt{\frac{3.2^2}{320}}

E = z \times \sqrt{\frac{10.24}{320}}

The z-value for 90% confidence level is 1.645.

Substitute 1.645 for z

E = 1.645 \times \sqrt{\frac{10.24}{320}}

E = 1.645 \times \sqrt{0.032}

Take square roots

E = 1.645 \times 0.1789

Multiply

E = 0.2943

Approximate

E = 0.29

Hence, the margin of error is 0.29

Read more about margin of error at:

brainly.com/question/14396648

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Evgesh-ka [11]

Amount of walnuts=\frac{3}{4} kg

Amount of almonds=\frac{1}{2} kg

Amount of pecans=\frac{1}{4} kg

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LCM is 4 so sum is = \frac{3+2+1}{4}=\frac{6}{4} =\frac{3}{2}

As given, Carmela divides the mixed nuts into 3/10 kilogram bags so number of bags will be:

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5 0
3 years ago
Select the correct similarity statement.
Nostrana [21]

Answer:

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Step-by-step explanation:

For two fugures to be considered similar, it means the corresponding sides are proportional, and as such, the ratio of their corresponding sides are equal.

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Taking a look at the figure of the triangle given, ∆STR is a right angle triangle, and it is similar to ∆RTQ as the angle formed at <T in ∆RTQ = 90°.

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The last option is correct.

4 0
3 years ago
50 POINTS + BRAINLIEST TO CORRECT ANSWER!! TRIG/GEO
WINSTONCH [101]

Option C:

We can find the value of PR using law of cosines.

Solution:

Given data:

∠Q = 18°, r = 9.5, p = 6.0

To find which length could be find in the triangle:

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a^{2}=b^{2}+c^{2}-2 b c \cos A

Substitute a = q, b = r, c = p and A = Q

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