5/(x^2-4)+2/x=2/(x-2) if we factor the leading denominator, it is a "difference of squares" of the form (a^2-b^2) which always factors to (a-b)(a+b) so we have:
5/((x-2)(x+2))+2/x=2/(x-2), to add/subtract fractions we need a common denominator, so in this case we need a common denominator of x(x-2)(x+2) so
5(x)+2(x+2)(x-2)=2(x)(x+2), perform indicated operations...
5x+2(x^2-4)=2x(x+2)
5x+2x^2-8=2x^2+4x subtract 2x from both sides
5x-8=4x subtract 4x from both sides
x-8=0 add 8 to both sides
x=8
check...
5/(x^2-4)+2/x=2/(x-2) when x=8 so
5/(64-4)+2/8=2/(8-2)
5/60+1/4=2/6
5/60+15/60=20/60
20/60=20/60
Answer:
n=-4
Step-by-step explanation:
-6n-(-2n)=16
-6n+2n=16
-4n=16
n=16/-4
n=-4
The tempurature at midnight was 19 degrees Fahrenheit.
Answer:
option 3 : (2x - 7 )
Step-by-step explanation:
ax + bx = x(a+ b)
a(x+ y) + b(x+y) = (x+y)(a+b)
![(3x - 8 ) ( 2x + 5) - (x + 1)(2x + 5)\\\\(2x+5)[ (3x - 8) - (x+1) ]](https://tex.z-dn.net/?f=%283x%20-%208%20%29%20%28%202x%20%2B%205%29%20-%20%28x%20%2B%201%29%282x%20%2B%205%29%5C%5C%5C%5C%282x%2B5%29%5B%20%283x%20-%208%29%20-%20%28x%2B1%29%20%5D)
[ (2x + 5) is common is both terms ]
Therefore , the binomial is ( 2x - 7)
Answer:
c
Step-by-step explanation:
the answer is 2
