Join for a maths intervention-foundation

Mathematics

1 answer:

In-s [12.5K]3 years ago

5 0

Answer:

$i \: wil \: join \: u \: for \\ maths \: intervention - fondation$

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Anybody can help me?

Leya [2.2K]

Its the first one, because x wont be affected, and 1 and -3 is a constant.

7 0

3 years ago

Graph the following equation using X- and y-intercepts. x + y = -3

Kitty [74]

Answer:

x-intercept: (-3,0)

y-intercept: (0,-3)

Step-by-step explanation:

Looking at the equation, we can see that it is already in standard form, or in a $Ax+By=C$ format. Whenever a line is put into standard form, the x-intercepts are represented by $(\frac{C}{A},0)$ and the y-intercepts are represented by $(0, \frac{C}{B} )$ . So, let's calculate them by doing the following:

1) Find the x-intercept by using the $(\frac{C}{A},0)$ formula. Substitute the number on the right side of the equation for $C$ and the coefficient for the x term for $A$ . So, in this case, $C = -3$ and $A = 1$ :

$(\frac{C}{A},0)\\\\(\frac{-3}{1},0) \\(-3,0)$

Therefore, the x-intercept is (-3,0).

2) Next, find the y-intercept by using the $(0,\frac{C}{B} )$ formula and substituting the right values. $C$ is still the number on the right side of the equation and $B$ is the coefficient of the y term. So, $C = -3$ and $B = 1$ .