(a).
The product of two binomials is sometimes called FOIL.
It stands for ...
the product of the First terms (3j x 3j)
plus
the product of the Outside terms (3j x 5)
plus
the product of the Inside terms (-5 x 3j)
plus
the product of the Last terms (-5 x 5)
FOIL works for multiplying ANY two binomials (quantities with 2 terms).
Here's another tool that you can use for this particular problem (a).
It'll also be helpful when you get to part-c .
Notice that the terms are the same in both quantities ... 3j and 5 .
The only difference is they're added in the first one, and subtracted
in the other one.
Whenever you have
(the sum of two things) x (the difference of the same things)
the product is going to be
(the first thing)² minus (the second thing)² .
So in (a), that'll be (3j)² - (5)² = 9j² - 25 .
You could find the product with FOIL, or with this easier tool.
______________________________
(b).
This is the square of a binomial ... multiplying it by itself. So it's
another product of 2 binomials, that both happen to be the same:
(4h + 5) x (4h + 5) .
You can do the product with FOIL, or use another little tool:
The square of a binomial (4h + 5)² is ...
the square of the first term (4h)²
plus
the square of the last term (5)²
plus
double the product of the terms 2 · (4h · 5)
________________________________
(c).
Use the tool I gave you in part-a . . . twice .
The product of the first 2 binomials is (g² - 4) .
The product of the last 2 binomials is also (g² - 4) .
Now you can multiply these with FOIL,
or use the squaring tool I gave you in part-b .
Answer: 
Step-by-step explanation:
Given
Length of the pipe 
Inside diameter of the pipe 
Outside diameter of the pipe 
Volume of the pipe
![\Rightarrow V=\dfrac{\pi }{4}[d_o^2-d_i^2]\\\\\text{Insert the values}\\\\\Rightarrow V=\dfrac{\pi}{4}[5^2-4^2]\times 10^{-4}\times 4\\\\\Rightarrow V=28.278\times 10^{-4}\ m^3\\\\\Rightarrow V=0.0028278\ m^3](https://tex.z-dn.net/?f=%5CRightarrow%20V%3D%5Cdfrac%7B%5Cpi%20%7D%7B4%7D%5Bd_o%5E2-d_i%5E2%5D%5C%5C%5C%5C%5Ctext%7BInsert%20the%20values%7D%5C%5C%5C%5C%5CRightarrow%20V%3D%5Cdfrac%7B%5Cpi%7D%7B4%7D%5B5%5E2-4%5E2%5D%5Ctimes%2010%5E%7B-4%7D%5Ctimes%204%5C%5C%5C%5C%5CRightarrow%20V%3D28.278%5Ctimes%2010%5E%7B-4%7D%5C%20m%5E3%5C%5C%5C%5C%5CRightarrow%20V%3D0.0028278%5C%20m%5E3)
Answer:
Well.. its already in standard form..
but even if u want u can write it as 8 X 10^(-1)
Step-by-step explanation:
Standard form is used for quite big decimal numbers
like : 0.2356
We can write it as 2.4 X 10^(-1)
Answer:
2/5
Step-by-step explanation:
Okay, since quotient is the answer to a division problem, you will divide w and -8. Increased means to add so, you will +7.
w/-8 +7 is what the expression looks like.