Question

Aleka and Helene both opened savings accounts that earn 2.5% interest a year. Aleka puts $2,500 into her account. Helene put $1,500 into her account and also saves $200 cash a year. x = number of years Aleka: f(x) = 2500(1.025)x Helene: g(x) = 1500(1.025)x + 200x Which function represents the difference, h(x) = f(x) – g(x), between the value of Aleka’s and Helene’s total savings after x years?

Answer 1

Answer:

C: h(x) = 1000(1.025)x – 200x

Step-by-step explanation:

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Answer 2

Answer:

$h(x)=1000(1.025)^x-200x$.

Step-by-step explanation:

We are given function f for Aleka's amount

$f(x)=2500(1.025)^x$

And function for Helene's amount

$g(x) = 1500(1.025)^x+200x$.

Now, we need to find the difference of the functions h(x) = f(x)-g(x).

Subtracting f(x) and g(x), function, we get

$h(x) =2500(1.025)^x-(1500(1.025)^x+200x)$

Distributing minus sign over second parenthesis, we get

$h(x) =2500(1.025)^x-1500(1.025)^x-200x$

Subtracting $2500(1.025)^x-1500(1.025)^x$, we get 1000.

Therefore, $h(x)=1000(1.025)^x-200x$.