What is 5 times 10 to the fifth?

Jake built a skateboard ramp, if the distance of the ramp is 10 ft. The ramp rises a

ikadub [295]

Answer:

Angle made by ramp with ground is ≈ $19.29^{\circ}$

Step-by-step explanation:

Diagram of given scenario is shown below.

Given that,

Horizontal Distance of Skateboard ramp is $10$ ft.

Height of Skateboard ramp is $3.5$ ft.

From figure,

It is forming a Right angle triangle $\triangle ABC$ .

In $\triangle ABC$ , $AB=3.5$ and $BC=10$ .

Clearly see that we need to find measure of angle $\angle C$ .

Using Trigonometric ratio:

$Tan(\theta)= \frac{Perpendicular}{Base}$

So, $Tan(\angle C) = \frac{AB}{BC} =\frac{3.5}{10} =0.35$

Then $\angle C=Tan^{-1} (3.5)=19.290046^{\circ}$

Therefore, Angle made by ramp with ground is ≈ $19.29^{\circ}$

8 0

3 years ago

How do you solve this

Nezavi [6.7K]

Answer:

this is how u solve this

Step-by-step explanation:

5 0

3 years ago

Select an operation to make the equation true.

MrRa [10]

Add. I’m not sure because there is a - besides the 15.

Explanation - 12 + 15 = 27.

Hopefully this helps. Have a blessed one. God loves you. ☺️

3 0

3 years ago

Assume that the paired data came from a population that is normally distributed. using a 0.05 significance level and dequalsxmin

Artemon [7]

"Assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and d = (x - y), find $\bar{d}$ , $s_{d}$ , the t-test statistic, and the critical values to test the claim that $\mu_{d} = 0$ "

You did not attach the data, therefore I can give you the general explanation on how to find the values required and an example of a random paired data.

For the example, please refer to the attached picture.

A) Find $\bar{d}$
You are asked to find the mean difference between the two variables, which is given by the formula:
$\bar{d} = \frac{\sum (x - y)}{n}$

These are the steps to follow:
1) compute for each pair the difference d = (x - y)
2) sum all the differences
3) divide the sum by the number of pairs (n)

In our example:
 $\bar{d} = \frac{6}{8} = 0.75$ 

B) Find $s_{d}$
You are asked to find the standard deviation, which is given by the formula:
 $s_{d} = \sqrt{ \frac{\sum(d - \bar{d}) }{n-1} }$

These are the steps to follow:
1) Subtract the mean difference from each pair's difference
2) square the differences found
3) sum the squares
4) divide by the degree of freedom DF = n - 1

In our example:
$s_{d} = \sqrt{ \frac{101.5}{8-1} }$
= √14.5
= 3.81

C) Find the t-test statistic.
You are asked to calculate the t-value for your statistics, which is given by the formula:
$t = \frac{(\bar{x} - \bar{y}) - \mu_{d} }{SE}$

where SE = standard error is given by the formula:
$SE = \frac{ s_{d} }{ \sqrt{n} }$

These are the steps to follow:
1) calculate the standard error (divide the standard deviation by the number of pairs)
2) calculate the mean value of x (sum all the values of x and then divide by the number of pairs)
3) calculate the mean value of y (sum all the values of y and then divide by the number of pairs)
4) subtract the mean y value from the mean x value
5) from this difference, subtract $\mu_{d}$
6) divide by the standard error

In our example:
SE = 3.81 / √8
= 1.346

The problem gives us $\mu_{d} = 0$ , therefore:
t = [(9.75 - 9) - 0] / 1.346
= 0.56

D) Find $t_{\alpha / 2}$
You are asked to find what is the t-value for a 0.05 significance level.

In order to do so, you need to look at a t-table distribution for DF = 7 and A = 0.05 (see second picture attached).

We find $t_{\alpha / 2} = 1.895$ 

Since our t-value is less than $t_{\alpha / 2}$ we can reject our null hypothesis!!

7 0

3 years ago

If m A.) 2 B.) 4 C.) 5 D.) 3

Arada [10]

Answer:

Miss gurl... the question not giving what its supposed to gave

Step-by-step explanation:

3 0

3 years ago