Question

An architect is creating a scale drawing of a school computer lab. The length of the lab is 32 feet and the width of the lab is 48 feet. If each 8 feet of the lab equals 2 centimeters on a scale drawing, which of the following drawings is the scale drawing of the computer lab? A rectangle is shown. The length of the rectangle is labeled as length equal to 4 cm and the width is labeled as width equal to 6 cm. A rectangle is shown. The length of the rectangle is labeled as length equal to 16 cm and the width is labeled as width equal to 32 cm. A rectangle is shown. The length of the rectangle is labeled as length equal to 24 cm and the width is labeled as width equal to 40 cm. A rectangle is shown. The length of the rectangle is labeled as length equal to 8 cm and the width is labeled as width equal to 12 cm.

Answer 1

8cm long
12 cm wide

32/8=4
4x2= 8
48/8=6
6x2=12

hope it helps! :) 
Sowwy if it didnt :'(

Answer 2

Answer:

Last option is the correct one.

Step-by-step explanation:

The following drawing is the scale drawing of the computer lab -The length of the rectangle is labeled as length equal to 8 cm and the width is labeled as width equal to 12 cm.

Given is : The length of the lab is 32 feet and the width of the lab is 48 feet and each 8 feet of the lab equals 2 centimeters on a scale drawing.

So, We will divide the actual length with 8 and multiply by 2 as 8 feet is equal to 2 cm.

So, length will be = $\frac{48}{8} \times2=12$ cm

Width will be = $\frac{32}{8} \times2=8$ cm

Hence, option D is correct.