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stiv31 [10]
3 years ago
8

Jessica opened the bank account that earns 2% interest compounded annually.can you deposit was $100 and she use the Expression $

100(x)^t to find the value of the account after t years.
what is the value of the x in the expression?
Mathematics
1 answer:
Drupady [299]3 years ago
4 0
Ok so compound interst formula is
F=A(1+ \frac{c}{n})^{nt}
where

F=future amount
A=present amount
c=percent interest in decimal form
n=number of times compoounded per year
t=times in years

A= present amount=100
c=2%=0.02
n=1 since once per year
t=t
so
F=100(1+(0.02)/1)^(1t)
F=100(1+0.02)^t
F=100(1.02)^t

x=1.02
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3 years ago
In 1998 the average income for middle class families in the US was $37,100 with a population standard deviation of $6362. We wan
sammy [17]

Answer:

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

The best answer would be:

A. Z test

Step-by-step explanation:

Data given and notation  

\bar X=36670 represent the mean average

\sigma=6362 represent the population standard deviation for the sample  

n=1225 sample size  

\mu_o =37100 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal or not to 37100, the system of hypothesis would be:  

Null hypothesis:\mu =37100  

Alternative hypothesis:\mu \neq 37100  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

The best answer would be:

A. Z test

5 0
3 years ago
Solve x2 + 2x + 9 = 0
Keith_Richards [23]
x^2+2x+9=0 \\ \\
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x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-2 \pm \sqrt{-32}}{2 \times 1}=\frac{-2 \pm \sqrt{-16 \times 2}}{2}=\frac{-2 \pm 4i\sqrt{2}}{2}=-1 \pm 2i\sqrt{2}

The answer is D.
8 0
3 years ago
Read 2 more answers
Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15. N an 1 4 2 −12 3 36 t
Rzqust [24]

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is                    \sum_{n=4}^{15} 5(-2)^{n-1}$$  

<h3>What is sequence ?</h3>

Sequence is collection of  numbers with some pattern .

Given sequence

a_{1}=5\\\\a_{2}=-10\\\\\\a_{3}=20

We can see that

\frac{a_1}{a_2}=\frac{-10}{5}=-2\\

and

\frac{a_2}{a_3}=\frac{20}{-10}=-2\\

Hence we can say that given sequence is Geometric progression whose first term is 5 and common ratio is -2

Now n^{th}  term of this Geometric progression can be written as

T_{n}= 5\times(-2)^{n-1}

So summation of 15 terms can be written as

\sum_{n=4}^{15} T_{n}\\\\$\\$\sum_{n=4}^{15} 5(-2)^{n-1}$$

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is                    \sum_{n=4}^{15} 5(-2)^{n-1}$$  

To learn more about Geometric progression visit : brainly.com/question/14320920

8 0
2 years ago
<img src="https://tex.z-dn.net/?f=6%5Csqrt%7B3%7D%2B2%281-%5Csqrt%7B27%7D%29%3D2" id="TexFormula1" title="6\sqrt{3}+2(1-\sqrt{27
skelet666 [1.2K]

Answer:

This is true.

Step-by-step explanation:

Step 1: see that √27 is the same as √3*3*3 and thus 3√3

Step 2: remove parenthesis so that 2(1-3√3) becomes 2 - 6√3

Step 3: observe that the equation now becomes 6√3 + 2 - 6√3 = 2

if you simplify any further, you are left with 0=0, which is true.

Comment if there is any step that requires more details...

3 0
3 years ago
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