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Tanzania [10]
3 years ago
11

Multiply: (9x^2y^3)(7xy^2)

Mathematics
2 answers:
love history [14]3 years ago
6 0
(9x²y³)(7xy²)

9 * 7 = 63
x² * x = x^2+1 = x³
y³ * y² = y^3+2 = y^5

<span>(9x²y³)(7xy²) = 63x</span>³y^5
MrRissso [65]3 years ago
5 0
Remember
(ab)(cd)=(a)(b)(c)(d)=(ac)(bd),
and
(x^m)(x^n)=x^(m+n)

(9x^2y^3)(7xy^2)=
(9)(x^2)(y^3)(7)(x)(y^2)=
(9)(7)(x^2)(x)(y^3)(y^2)=
(63)(x^3)(y^5)=
63x^3y^5
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Approximatley 5.8 units.

Step-by-step explanation:

We are given two angles, ∠S and ∠T, and the side opposite to ∠T. We need to find the unknown side opposite to ∠S. Therefore, we can use the Law of Sines. The Law of Sines states that:

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Solve for <em>s</em>, the unknown side. Cross multiply:

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Answer:

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