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Tanya [424]
2 years ago
15

Write the equation of a line that is parallel to {y=0.6x+3}y=0.6x+3y, equals, 0, point, 6, x, plus, 3 and that passes through th

e point {(-3,-5)}(−3,−5)left parenthesis, minus, 3, comma, minus, 5, right parenthesis.
Mathematics
1 answer:
Dominik [7]2 years ago
3 0

y = 0.6x - 3.2  
The general form of the desired equation is 
y = mx + b
 where
 m = slope of the line
 b = y intercept of the line 
 If two lines are parallel, their slopes will be the same, Since the slope of the
given line "y = 0.6x +3" is 0.6, that will also be the slope of the desired line.
So our equation becomes:
 y = 0.6x + b 
 Now we can substitute the x and y value of the desired point we want the new line to pass through and find b. So
 y = 0.6x + b
 -5 = 0.6(-3) + b
 -5 = -1.8 + b
 -3.2 = b 
 So the desired equation is now 
y = 0.6x - 3.2
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8 0
3 years ago
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solniwko [45]

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8 people

Step-by-step explanation:

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7 0
2 years ago
ASAP PLSS
Vinil7 [7]
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6 0
2 years ago
Can somebody please help me with this please I would realllyy appreciate it !
Nuetrik [128]
While I'd be very glad to help you reasonably, I don't find your posting 10 questions at once to be reasonable.

Here's ONE of the problems:    -2m^2 + 5mn
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8 0
3 years ago
Which of the following points would fall on the line produced by the point-slope form equation y-3= 5(x + 3) when graphed?
olya-2409 [2.1K]
First, solve the given equation:

y-3 = 5(x+3) Original equation
y-3 = 5x+15 Distributed the parenthesis
y = 5x+15+3 Isolated y by grouping like-terms
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Then, you’d plug in the sets of coordinates. The first is (-3,3). X is -3 and Y is 3 because coordinates are written in (x,y) format.

(3) = 5(-3)+18

3 = -15+18

3 = 3

Since the first coordinates (-3,3) are correct, there is no need to try the other equations.
4 0
1 year ago
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