Question

Write the equation of a line that is parallel to {y=0.6x+3}y=0.6x+3y, equals, 0, point, 6, x, plus, 3 and that passes through the point {(-3,-5)}(−3,−5)left parenthesis, minus, 3, comma, minus, 5, right parenthesis.

Answer 1

y = 0.6x - 3.2  
The general form of the desired equation is 
y = mx + b
 where
 m = slope of the line
 b = y intercept of the line 
 If two lines are parallel, their slopes will be the same, Since the slope of the
given line "y = 0.6x +3" is 0.6, that will also be the slope of the desired line.
So our equation becomes:
 y = 0.6x + b 
 Now we can substitute the x and y value of the desired point we want the new line to pass through and find b. So
 y = 0.6x + b
 -5 = 0.6(-3) + b
 -5 = -1.8 + b
 -3.2 = b 
 So the desired equation is now 
y = 0.6x - 3.2