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Tanya [424]
3 years ago
15

Write the equation of a line that is parallel to {y=0.6x+3}y=0.6x+3y, equals, 0, point, 6, x, plus, 3 and that passes through th

e point {(-3,-5)}(−3,−5)left parenthesis, minus, 3, comma, minus, 5, right parenthesis.
Mathematics
1 answer:
Dominik [7]3 years ago
3 0

y = 0.6x - 3.2  
The general form of the desired equation is 
y = mx + b
 where
 m = slope of the line
 b = y intercept of the line 
 If two lines are parallel, their slopes will be the same, Since the slope of the
given line "y = 0.6x +3" is 0.6, that will also be the slope of the desired line.
So our equation becomes:
 y = 0.6x + b 
 Now we can substitute the x and y value of the desired point we want the new line to pass through and find b. So
 y = 0.6x + b
 -5 = 0.6(-3) + b
 -5 = -1.8 + b
 -3.2 = b 
 So the desired equation is now 
y = 0.6x - 3.2
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Answer:

The general form of a natural logarithmic function is <em>f(x)=a In(x-h) +k.</em> Since the initial average length of the lizards was 20 centimeters, one possible point (h+1,k) through which the function passes is (0,20).

In this case, h= -1 since h +1 = 0 and k = 20.

It follows that x - h = (-1) = x + 1.

So, the function takes the form <em>f(x) = a In(x + 1) +20. </em>

The average length of the lizards after 2 years is 22.197. So f(2) =22.197. We substitute this value into the function

Step-by-step explanation:

<em>f(2) = a In(2 +1) +20 </em>

<em>22.197 = a In(3) + 20 </em>

<em></em>\frac{2.197}{1.099}<em>≈ a </em>

<em>2 ≈ a</em>

So the function that represents the average length of the lizards across this generation is <em>f(x) = 2 In(x+1) +20 </em>

3 0
3 years ago
What is the value of A, B, and C?
Varvara68 [4.7K]

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4 0
3 years ago
Need answer ASAP <br> *MARKING BRAINLIEST
Luba_88 [7]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
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Car A has an initial value of 30,000 and depreciates at a rate of 20% per year. Car B has an initial value of 20,000 and depreci
Doss [256]

Answer:

The value of Car B will become greater than the value of car A during the fifth year.

Step-by-step explanation:

Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.

In the attached excel file, the following are used:

Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000

Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000

Annual Depreciation expense of Car B in Year 7 =  Beginning value of Car B in Year 7 = 2,000

Conclusion

Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.

Download xlsx
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