y = 0.6x - 3.2 The general form of the desired equation is y = mx + b where m = slope of the line b = y intercept of the line If two lines are parallel, their slopes will be the same, Since the slope of the given line "y = 0.6x +3" is 0.6, that will also be the slope of the desired line. So our equation becomes: y = 0.6x + b Now we can substitute the x and y value of the desired point we want the new line to pass through and find b. So y = 0.6x + b -5 = 0.6(-3) + b -5 = -1.8 + b -3.2 = b So the desired equation is now y = 0.6x - 3.2
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