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ExtremeBDS [4]
4 years ago
12

What is the solution to the system of equations?

Mathematics
1 answer:
yarga [219]4 years ago
8 0

Answer:

(2, - 4 )

Step-by-step explanation:

Given the 2 equations

x + 2y = - 6 → (1)

3x + y = 2 → (2)

Multiplying (2) by - 2 and adding to (1) will eliminate the term in y

- 6x - 2y = - 4 → (3)

Add (1) and (3) term by term to eliminate y

- 5x = - 10 ( divide both sides by - 5 )

x = 2

Substitute x = 2 into either of the 2 equations and solve for y

Substituting into (1)

2 + 2y = - 6 ( subtract 2 from both sides )

2y = - 8 ( divide both sides by 2 )

y = - 4

Solution is (2, - 4 )

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PLEASE HELP ANSWER THESE QUESTIONS!
Sliva [168]

Answer:

Step-by-step explanation:

a² - b² = (a+ b)(a - b)

1) (2n-4/2n) ÷ (n^2-4/n)

=\frac{2n-4}{2n}*\frac{n}{n^{2}-4}\\\\=\frac{2n-2*2}{2n}*\frac{n}{n^{2}-2^{2}}\\\\=\frac{2*(n-2)}{2n}*\frac{n}{(n+2)*(n-2)}\\\\=\frac{1}{n+2}

2) [y^2-36/y^2-49] ÷[ y+6/y-7]

=\frac{y^{2}-36}{y^{2}-49}*\frac{y-7}{y+6}\\\\=\frac{y^{2}-6^{2}}{y^{2}-7^{2}}*\frac{y-7}{y+6}\\\\=\frac{(y+6)*(y-6)}{(y+7)*(y-7)}*\frac{y-7}{y+6}\\\\=\frac{y-6}{y+7}\\

3) [m^2-1/ m^2-m] ÷ [m^2-7m-8/3m ]

=\frac{m^{2}-1}{m^{2}-m}*\frac{3m}{m^{2}-7m-8}\\\\=\frac{(m+1)*(m-1)}{m*(m-1)}*\frac{3m}{(m-8)*(m+1)}\\\\=\frac{3}{m-8}

Hint :  m² - 7m - 8

sum = -7

Product  = -8

Factor = (-8), 1

m² - 7m - 8  =m² - 8m + m - 8

                   = m*(m - 8) + (m-8)

                   = (m - 8)(m +1)

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3 years ago
Solve for x.
Kay [80]

(4x+7)(2x+5) Like this???

4x+7=2x+5 or like this?!!?!

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ryzh [129]

Answer: A

Step-by-step explanation:

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2 years ago
Given the parent function f(x)=x^2 describe the graph of y=(0.2x)^2
Yanka [14]
We have the following function:
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3 years ago
Rafael is taking a test that contains a section of 12 true-false questions. How many of the possible groups of answers to these
Klio2033 [76]
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