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3 years ago

Can someone plz help me with this one problem plzzz!!!

Mathematics

1 answer:

tresset_1 [31]3 years ago

6 0

so, you just use the x's from the table and plug them into the equation to find the y.

y=(1)+9

y=10

y=(2)+9

y=11

y=(3)+9

y=12

y=(4)+9

y=13

i hope this helps :)

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Answer:

$P(x) = x^{2} + x(5-4i) - 20i$ is the required polynomial function of the form $ax^{2} + bx +c$

Step-by-step explanation:

The given zeroes of the polynomial is -5 and 4i.

It implies, the roots of the polynomial is (x+5) and (x-4i)

Now, The Polynomial = Product of all its roots

So, here P(x) = ( x + 5)( x - 4i)

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Answer: $2x^{2} + 5x -3$

Step-by-step explanation:

Find the quotient of $\frac{16x^4+40x^3-24x^2}{8x^2}$

Step 1: Break down the polynomial equation

$\frac{16x^4}{8x^2}$ + $\frac{40x^3}{8x^2}$ - $\frac{24x^2}{8x^2}$

Step 2: Divide each piece by dividing the coeffients and subtracting the variables.

16 ÷ 8 = 2

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40 ÷ 8 = 5

$x^{3}$ - $x^{2}$ = $x$ → 5 $x$

- 24 ÷ 8 = - 3

$x^{2}$ - $x^{2}$ = 1 → - 3

Step 3: Put the polynomial together

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