Question

Can someone please help me with this? will give you brainiest if correct

Answer 1

Answer: The solution is [2, 1]

Step-by-step explanation:

The given system of simultaneous equations is expressed as

7x - 6y = - 20 - - - - - - - - - - 1

3x + 5y = - 1 - - - - - - - - - - - - -2

We would eliminate x by multiplying equation 1 by 3 and equation 2 by 7. It becomes

21x - 18y = - 60 - - - - - - - - - - 3

21x + 35y = - 7 - - - - - - - - - - 4

Subtracting equation 4 from equation 3, it becomes

- 53y = - 53

Dividing the left hand side and the right hand side of the equation by - 53, it becomes

- 53y/ - 53 = - 53/ - 53

y = 1

Substituting y = 1 into equation 2, it becomes

3x + 5 × 1 = - 1

3x + 5 = - 1

Subtracting 5 from the left hand side and the right hand side of the equation, it becomes

3x + 5 - 5 = - 1 - 5

3x = - 6

Dividing the left hand side and the right hand side of the equation by 3, it becomes

3x/3 = - 6/3

x = 2