Step-by-step explanation:
f(x) = 1/3|x|
then
f(x) = 1/3x , if x ≥ 0
and
f(x) = -1/3x , if x ≤ 0
the slope of f(x) = 1/3x is 1/3
the slope of f(x) = -1/3x is -1/3
this two above conditions apply on to the fourth graph to the right.
For this case we have the following equation:

We must clear the value of the variable "x" as a function of r, s and t:
If we multiply by "r" on both sides of the equation we have:

If we subtract "t" on both sides of the equation we have:

If we divide by "2" on both sides of the equation we have:

Thus, the value of the variable "x" is:

Answer:

y= -4x² - 16x - 14
Take the coefficient of x² as the common factor
y = - 4(x² + 4x + 7/2)
Add (b/2)² to complete the square
y = - 4( x² + 4x + 2² - 2² + 7/2)
Complete the square
y = -4( (x + 2)² - 1/2)
Remove the bracket
y = -4(x + 2)² + 2
Answer: y = -4(x + 2)² + 2
Answer:
The slope of line t is -4/5.
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(14-10)/(2-7)
m=4/-5
Parallel lines have same slopes.