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Luden [163]
3 years ago
13

If there are 1/2 cup of almonds how many more would you need for a third

Mathematics
1 answer:
irga5000 [103]3 years ago
5 0
1/6 of almonds. you multiply the two numbers together.
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Layla calculates the mean of the ages of 10 students on her bus, and she discovers the average(mean) age is 12.8. What will happ
Papessa [141]
Hey it’s 42 but carry the two to answer the two to my my
7 0
3 years ago
Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant​ criteria?Tem
Xelga [282]

Answer:

B. No, this distribution does not appear to be normal

Step-by-step explanation:

Hello!

To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.

The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.

As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.

The answer is B.

I hope it helps!

3 0
3 years ago
Two planes are the same altitude. From the airport , one plane is 50 km away in the direction of N°60 E and another is 80 km awa
djverab [1.8K]

9514 1404 393

Answer:

  78.5 km

Step-by-step explanation:

Measured at the airport, the angle between the two planes is ...

  180° -60° -50° = 70°

The law of cosines tells us the distance between the planes is ...

  d = √(50² +80² -2·50·80·cos(70°)) ≈ √6163.84 ≈ 78.5 . . . km

The planes are about 78.5 km apart.

6 0
3 years ago
The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum
wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information:P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000, where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2

Equating it to zero we get,

x^2 + 36x - 6400 = 0

We use the quadratic formula to find the values of x:

x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}, where a, b and c are coefficients of x^2, x^1 , x^0 respectively.

Putting these value we get x = -100, 64

Now, again differentiating

\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x

At x = 64,  \displaystyle\frac{d^2(P(x))}{dx^2} < 0

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0
3 years ago
Plz plz hurry plz hurry plz hurry
e-lub [12.9K]
The answer is C that can be the x-intercepts of the parabola
6 0
3 years ago
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