Answer:
10%
Step-by-step explanation:
We know Perimeter of rectangle
= 2 (Length + Width)
If width and length are increased by 10%
New length= L + 10/100L = (1.1) L
New width = W + 10/100W = (1.1) W
Perimeter = 2 [(1.1) L + (1.1) W]
Perimeter = 2 (1.1) (L + W)
Perimeter = (2.2) (L + W)
Increase in perimeter = 2.2 (L + W) - 2 (L + W)
The increase in Perimeter = 0.2 (L + W)
Percent increase
= 0.2 (L + W)/2 (L + W) × 100
= 0.2/2 × 100
= 0.1 × 100
= 10%
I hope this helped and if it did, please mark as Brainliest.
Answer:
12 pieces of fabric
Step-by-step explanation:
3 / 0.25 = 12
Solve the following system using substitution:
{y + 2.3 = 0.45 x
{-2 y = -3.6
In the second equation, look to solve for y:
{y + 2.3 = 0.45 x
{-2 y = -3.6
-3.6 = -18/5:
-2 y = -18/5
Divide both sides by -2:
{y + 2.3 = 0.45 x
{y = 9/5
Substitute y = 9/5 into the first equation:
{4.1 = 0.45 x
{y = 9/5
In the first equation, look to solve for x:
{4.1 = 0.45 x
{y = 9/5
4.1 = 41/10 and 0.45 x = (9 x)/20:
41/10 = (9 x)/20
41/10 = (9 x)/20 is equivalent to (9 x)/20 = 41/10:
{(9 x)/20 = 41/10
{y = 9/5
Multiply both sides by 20/9:
Answer: {x = 82/9
{y = 9/5
Hello!
Here are some rules to determine the number of significant figures.
- Numbers that are not zero are significant (45 - all are sigfigs)
- Zeros between non-zero digits are significant (3006 → all are sigfigs)
- Trailing zeros are not significant (0.067 → the first two zeros are not sigfigs)
- Trailing zeros after a decimal point are always significant (1.000 → all are sigfigs)
- Trailing zeros in a whole number are not significant (7800 → the last two zeros are not sigfigs)
- In scientific notation, the exponential digits are not significant, known as place holders (6.02 x 10² → 10² is not a sigfig)
Now, let's find the number of significant figures in each given number.
A). 296.54
Since these digits are all <em>non-zero</em>, there are 5 significant figures.
B). 5003.1
Since the two <em>zeros are between non-zero digits</em>, they are significant figures. Thus, there are 5 significant figures.
C). 360.01
Again, the two zeros are between non-zero digits. There are 5 significant figures.
D). 18.3
All of these digits are non-zero, hence, there are 3 significant figures.
Therefore, expression D has the fewest number of significant figures being 3.
