Answer:
1022.50
Step-by-step explanation:
1000*.03= 30. (12mos interest)
30/4=7.50 quarterly interest
7.50x3 (9mos)= 22.50 interest
Answer:
x=sqrt(3)/2 or -sqrt(3)/2
Step-by-step explanation:
(x,1/2) is on the unit circle at pi/6 and 5pi/6.
so x is either sqrt(3)/2 or -sqrt(3)/2
Id say 40%
because 8 are math so 9 of them are other
Answer:
A) x = 3 or -1
B) x = -7
C)x = -7
Step-by-step explanation:
A) x² + 2x + 1 = 2x² - 2
Rearranging, we have;
2x² - x² - 2x - 2 - 1 = 0
x² - 2x - 3 = 0
Using quadratic formula, we have;
x = [-(-2) ± √((-2)² - 4(1 × -3))]/(2 × 1)
x = (2 ± √16)/2
x = (2 + 4)/2 or (2 - 4)/2
x = 6/2 or -2/2
x = 3 or -1
B) ((x + 2)/3) - 2/15 = (x - 2)/5
Multiply through by 15 to get;
5(x + 2) - 2 = 3(x - 2)
5x + 10 - 2 = 3x - 6
5x - 3x = -6 - 10 + 2
2x = -14
x = -14/2
x = -7
C) log(2x + 3) = 2log x
From log derivations, 2 log x is same as log x²
Thus;
log(2x + 3) = logx²
Log will cancel out to give;
2x + 3 = x²
x² - 2x - 3 = 0
Using quadratic formula, we have;
x = [-(-2) ± √((-2)² - 4(1 × -3))]/(2 × 1)
x = (2 ± √16)/2
x = (2 + 4)/2 or (2 - 4)/2
x = 6/2 or -2/2
x = 3 or -1
Answer:
The speed of jogger in uphills is 4 mile per hour
And The speed of jogger in downhills is 10 mile per hour
Step-by-step explanation:
Given as :
The distance cover by jogger in downhill (Dd) = 5 miles
The distance cover by jogger in uphill (Du) = 2 miles
The time taken by jogger in downhill (Td) = T hour
The time taken by jogger in uphill (Tu) = T hour
Let The speed of jogger in uphills (Su) = x mph
So ,The speed of jogger in downhills (Sd) =( x + 6 ) mph
∵, Time = 
So, Tu = 
Or, T = 
h
And Td = 
Or, T = 
h
∵ Time duration of both is same
∴ =
Or, 2 × (x + 6) = 5x
Or, 2x + 12 = 5x
So, 12 = 3x
∴ x = 
= 4 mph
And x + 6 = 4 + 6 = 10 mph
Hence The speed of jogger in uphills is 4 mile per hour
And The speed of jogger in downhills is 10 mile per hour Answer
