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svlad2 [7]
3 years ago
8

If Alejandro walks 3 miles in 43 minutes, then how far will Austin walk in 93 minutes?

Mathematics
1 answer:
san4es73 [151]3 years ago
7 0

Answer:

Step-by-step explanation:

43min=3miles

93min=3*93=279/43

austin will walk 6.488miles for 93 minutes

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Mr. Altamirano opens an account with a simple interest on an account with $1000 at 3% annually for 9 months. How much interest d
gladu [14]

Answer:

1022.50

Step-by-step explanation:

1000*.03= 30. (12mos interest)

30/4=7.50 quarterly interest

7.50x3 (9mos)= 22.50 interest

7 0
3 years ago
the point P = (x, 1/2) lies on the unit curcle shown below. what is the value of x in the simplest form
Mrac [35]

Answer:

x=sqrt(3)/2 or -sqrt(3)/2

Step-by-step explanation:

(x,1/2) is on the unit circle at pi/6 and 5pi/6.

so x is either sqrt(3)/2 or -sqrt(3)/2

5 0
3 years ago
Joanna needs a book to prop up a table leg. She randomly selects a book , and selects another book . What is probability that sh
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Id say 40%
because 8 are math so 9 of them are other 
3 0
3 years ago
All three please 10 points
GaryK [48]

Answer:

A) x = 3 or -1

B) x = -7

C)x = -7

Step-by-step explanation:

A) x² + 2x + 1 = 2x² - 2

Rearranging, we have;

2x² - x² - 2x - 2 - 1 = 0

x² - 2x - 3 = 0

Using quadratic formula, we have;

x = [-(-2) ± √((-2)² - 4(1 × -3))]/(2 × 1)

x = (2 ± √16)/2

x = (2 + 4)/2 or (2 - 4)/2

x = 6/2 or -2/2

x = 3 or -1

B) ((x + 2)/3) - 2/15 = (x - 2)/5

Multiply through by 15 to get;

5(x + 2) - 2 = 3(x - 2)

5x + 10 - 2 = 3x - 6

5x - 3x = -6 - 10 + 2

2x = -14

x = -14/2

x = -7

C) log(2x + 3) = 2log x

From log derivations, 2 log x is same as log x²

Thus;

log(2x + 3) = logx²

Log will cancel out to give;

2x + 3 = x²

x² - 2x - 3 = 0

Using quadratic formula, we have;

x = [-(-2) ± √((-2)² - 4(1 × -3))]/(2 × 1)

x = (2 ± √16)/2

x = (2 + 4)/2 or (2 - 4)/2

x = 6/2 or -2/2

x = 3 or -1

5 0
3 years ago
A jogger runs 6 miles per hour faster downhill than uphill. If the jogger can run 5 miles downhill in the same time that it take
muminat

Answer:

The speed of jogger in uphills is 4 mile per hour  

And  The speed of jogger in downhills is 10 mile per hour

Step-by-step explanation:

Given as :

The distance cover by jogger in downhill (Dd) = 5 miles

The distance cover by jogger in uphill     (Du)  = 2 miles

The time taken by jogger in downhill       (Td)  = T  hour

The time taken by jogger in uphill            (Tu)  = T hour

Let The speed of jogger in uphills            (Su)  = x mph

So ,The speed of jogger in downhills      (Sd)  =( x + 6 ) mph

∵, Time = \frac{Distance}{Speed}

So, Tu = \frac{Du}{Su}

Or, T = \frac{2}{x}   h

And Td = \frac{Dd}{Sd}

Or,   T = \frac{5}{(x + 6)}  h

∵  Time duration of both is same

∴  \frac{2}{x} = \frac{5}{(x + 6)}

Or,  2 × (x + 6) = 5x

Or,  2x + 12 = 5x

So,    12 = 3x

∴       x = \frac{12}{3} = 4 mph

And  x + 6 = 4 + 6 = 10 mph

Hence The speed of jogger in uphills is 4 mile per hour  

And      The speed of jogger in downhills is 10 mile per hour   Answer

5 0
3 years ago
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