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sweet [91]
3 years ago
10

Which expression has the fewest significant figures?

Mathematics
2 answers:
pickupchik [31]3 years ago
5 0

Answer:

d

Step-by-step explanation:

yanalaym [24]3 years ago
4 0

Hello!

Here are some rules to determine the number of significant figures.

  1. Numbers that are not zero are significant (45 - all are sigfigs)
  2. Zeros between non-zero digits are significant (3006 → all are sigfigs)
  3. Trailing zeros are not significant (0.067 → the first two zeros are not sigfigs)
  4. Trailing zeros after a decimal point are always significant (1.000 → all are sigfigs)
  5. Trailing zeros in a whole number are not significant (7800 → the last two zeros are not sigfigs)
  6. In scientific notation, the exponential digits are not significant, known as place holders (6.02 x 10² → 10² is not a sigfig)

Now, let's find the number of significant figures in each given number.

A). 296.54

Since these digits are all <em>non-zero</em>, there are 5 significant figures.

B). 5003.1

Since the two <em>zeros are between non-zero digits</em>, they are significant figures. Thus, there are 5 significant figures.

C). 360.01

Again, the two zeros are between non-zero digits. There are 5 significant figures.

D). 18.3

All of these digits are non-zero, hence, there are 3 significant figures.

Therefore, expression D has the fewest number of significant figures being 3.  

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123456789 x 125 ÷ 4<br><br> I will mark brainiest!!!!!
erica [24]

Do PEMDAS! Multiply and divide from left to right. 123456789 x 125 is 15432098625, and now we divide by 4, giving us 3858024656.25, but rounded to the nearest whole number (ones) is 3858024656.

Hope this helped!

Nate

5 0
3 years ago
The store currently has seven rackets of each version. What is the probability that all of the next ten customers who want this
Mila [183]

The probability that all of the next ten customers who want this racket can get the version they want from current stock is 0.821

<h3>How to solve?</h3>

Given: currently has seven rackets of each version.

Then the probability that the next ten customers get the racket they want is P(3≤X≤7)

<h3>Why P(3≤X≤7)?</h3>

Note that If less than 3 customers want the oversize, then more than 7 want the midsize and someone's going to miss out.

X ~ Binomial (n = 10, p = 0.6)

P(3≤X≤7)  = P(X≤7) - P(X≤2)

From Binomial Table:

               = 0.8333 - 0.012

               = 0.821

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6 0
2 years ago
3 soccer balls and 5 more how many are there​
vodomira [7]

Answer:

8

Step-by-step explanation:

3+5=8

6 0
3 years ago
Let's consider the time as a discrete variable with an increment of 1 minute. You arrive at a bus stop at 10 AM, knowing that th
Dafna11 [192]

Answer:

a) 2/3

b) 1/3

Step-by-step explanation:

Let X be the random event that measures the time you will have to wait.  

Since time is uniformly distributed between 10 and 10:30 in intervals of 1 minute

P(n < X ≤ n+1) = 1/30 for every minute n=0,1,...29.

a)

P( X > 10) = 1 - P(X ≤ 10) = 1 - 10/30 = 2/3

b)

P(10 <  X ≤ 20) = (20-10)/30 = 1/3

7 0
3 years ago
What is the value of the exponential expression5^0
rosijanka [135]
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