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slava [35]
3 years ago
10

One linear function, t(x), can be modeled by the values in the table below. A second linear function can be modeled by the equat

ion 3x − 2y + 6 = 0. When comparing the x-intercepts of these lines, which function has the largest x-intercept and what is this value?
x t(x)
−2 −15
−1 −10
0 −5
1 0
2 5
t(x) has the largest x-intercept: 1.
3x − 2y + 6 = 0 has the largest x-intercept: 3.
t(x) has the largest x-intercept: −5.
3x − 2y + 6 = 0 has the largest x-intercept: −2.
Mathematics
2 answers:
enyata [817]3 years ago
7 0
At x-intercept, y value = 0,
 
For t(x), x = 1 when y = 0, i.e. x-intercept = 1

for 3x - 2y + 6 = 0, when y = 0,
3x - 2(0) + 6 = 0
3x + 6 = 0
3x = -6
x = -6/3 = -2
i.e. x-intercept = -2

Therefore, t(x) has the highest x-intercept of 1.
lana66690 [7]3 years ago
6 0

That answer is wrong. the correct answer is C.

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PtichkaEL [24]

Hey there!!

How do we find the distance between two coordinate points?

In order to find the distance, we use this formula :

\sqrt{( x2 - x1 )^{2} + (y2-y1)^{2}}

The given coordinates :

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\sqrt{(4-(-2)^{2} + (-6-2)^{2}}

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4 years ago
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Answer:

h=13

P=5

b=12

Step-by-step explanation:

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  3. <em>c</em><em>o</em><em>s</em><em>A</em><em>=</em><em>b</em><em>÷</em><em>h</em><em>=</em><em>1</em><em>2</em><em>÷</em><em>1</em><em>3</em>
4 0
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fgiga [73]

Answer:

your answer will be Option C.256

Step-by-step explanation:

hope it helps

5 0
3 years ago
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DerKrebs [107]

550 sq m

Step-by-step explanation:

Step 1 :

The length of the first cross road the park  is 70 m

The width of the first cross road the park  is 5 m

So its area is 70 * 5  = 350 sq m

Step 2 :

The length of the second cross road the park  is 45 m

The width of the width cross road the park  is 5 m

So its area is 45 * 5 = 225 sq m

Step 3 :

The 2 cross roads intersect in the middle at an area of 5 * 5 = 25 sq m

This area is included in the computation of the area of both the cross roads and hence we need to subtract this area from the sum of the area of both the cross roads to obtain the actual area of cross roads in the park

So we have

the area of the cross roads inside the park = 350 + 225 - 25 = 550 sq m

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