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2 years ago

Can someone answer this

Mathematics

1 answer:

VladimirAG [237]2 years ago

8 0

The order of the graphs from largest to lowest correlation coefficients is:

Graph D, Graph A, graph C, graph B.

<h3>Which graph has the largest correlation coefficient?</h3>

The correlation coefficient between two variables is a coefficient that tells us "how much" these variables relate.

So, in the case for linear correlation, as "more linear" the data appears to be, a large correlation is between the two variables.

With that in mind, we conclude that the order of the graphs (going for larger correlation coefficient to smaller correlation coefficient) is:

Graph D, Graph A, graph C, graph B.

If you want to learn more about correlation:

brainly.com/question/4219149

#SPJ1

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A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4

Vladimir79 [104]

Answer:

The time interval when $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

$V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)$

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

$V_Q(t) \geq 60$ between $0 \leq t \leq 4$

The schematic free body graphical representation of the above illustration was attached in the file below and the point when $V_Q(t) \geq 60$ is at 4 is obtained in the parabolic curve.

So, $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

Taking the integral of the time interval in order to determine the distance; we have:

distance = $\int\limits^{3.519}_{1.866} {V_Q(t)} \, dt$

= $\int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt$

= By using the Scientific calculator notation;

distance = 106.109 m

4 0

3 years ago

I WAS ONLY ABLE TO SELECT 40 PTS THIS TIME, PLS ANSWER THIS ONE IT HAS THE PICTURE WITH IT.

BaLLatris [955]

Okay so the first one is right.
The second one is wrong.
the third one is right.
The forth one is wrong.

4 0

3 years ago

Read 2 more answers

There is a vendor at a carnival selling bags of cotton candy. Each bag of cotton candy has the same cost. She starts each day wi

umka21 [38]

Answer:

The cost of each cotton candy bag is $4.

Step-by-step explanation:

Consider the provided information.

Let, the vendor has $x$ dollar at the starting of each day.

Let, the cost of each cotton candy bag is $y$ .

Now when she sells a total of 12 bags, she has $128.

$x+12y=128$ .....(1)

After she sells a total of 20 bags, she has $160.

$x+20y=160$ ....(2)

Subtract equation 1 from equation 2.

$(x+20y)-(x+12y)=160-128$

$8y=32$

$y=4$

Hence, the cost of each cotton candy bag is $4.

6 0

3 years ago

What is the scientific notation of 6174798604

lesantik [10]

Here is your answer:

Since their no zeros (0) here's your answer:

6.174798604×10^9

7 0

3 years ago

I need help I can't figure out how to do this. I have to find the value of v. 4/5(v−7)=2

Nina [5.8K]

9.5 because 9.5-7 is 2.5. 2.5 times 4/5 is 10/5 which is equivalent to 2. 4/5(2.5-7)=2

7 0

4 years ago