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SSSSS [86.1K]
3 years ago
12

A drawing of a garden uses a scale of 1 in 3 ft. Find the length of the drawing is 13 inches

Mathematics
1 answer:
bagirrra123 [75]3 years ago
4 0
So we know each inch is 3 feet.

1:3.

13:?

So we multiply 13 by 3 to get the answer!

13:39

or 39 feet!

I hope this helped! :))

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Multiply 2/33•1/5•11/10 in simplest form
taurus [48]
2/33 * 1/5 * 11/10 = (2 * 1 * 11) / (33 * 5 * 10) = 22/1650 reduces to 1/75
6 0
3 years ago
Please help #22 please sos
iragen [17]
1/5( 5/2 x 4/7 -11/7) + 3/28

Multiply the terms (5/2 x 4/7) in bracket then subtract it from 11/14. Result will be 10/7.

Then multiply 1/5 with 10/7. The result will be 2/7.

2/7 + 3/28 = 11/28

T
4 0
3 years ago
Read 2 more answers
Thank you guys so much
jeka57 [31]

Answer:

B. City P is above sea level and City R is below sea level

Step-by-step explanation:

A. City R is negative meaning it is below sea level however City Q is 0 meaning it is at sea level, so this statement is false.

C. Once again, City P is positive meaning it is above sea level but City Q is 0 meaning it is at sea level, so this statement is false.

D. Like before, City P is above sea level and City Q is at sea level not below, so this is, once again, false.

6 0
3 years ago
6. I NEED HELP ASAP!! PLEASE PUT AND ANSWER AND STEP BY STEP EQUATION!! IF YOU DON'T KNOW THE ANSWER DON'T PUT ANYTHING!!
kramer

Answer:

I think the answer is B. f(x) = -1/3x - 4

Step-by-step explanation:

Use the given functions to set up and simplify  

4−16.

XF(x)=X

Fx

1 − 7 = −6

2 − 10 = −8

3 − 13 = −10

4 − 16 = −12

8 0
3 years ago
A man starts at a point A and walks 18 feet north. He then turns and walks due east at 18 feet per second. If a searchlight plac
34kurt

Answer:

1/10 per sec

Step-by-step explanation:

When he's walked x feet in the eastward direction, the angle Θ that the search light makes has tangent

tanΘ = x/18

Taking the derivative with respect to time

sec²Θ dΘ/dt = 1/18 dx/dt.

He's walking at a rate of 18 ft/sec, so dx/dt = 18.

After 3seconds,

Speed = distance/time

18ft/sec =distance/3secs

x = 18 ft/sec (3 sec)

= 54ft. At this moment

tanΘ = 54/18

= 3

sec²Θ = 1 + tan²Θ

1 + 3² = 1+9

= 10

So at this moment

10 dΘ/dt = (1/18ft) 18 ft/sec = 1

10dΘ/dt = 1

dΘ/dt = 1/10 per sec

8 0
3 years ago
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