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Colt1911 [192]
3 years ago
11

NEED HELP QUICK

Mathematics
1 answer:
Zinaida [17]3 years ago
8 0

(- 5, - 6 )

for x- coordinate x + 5 = 0 ⇒ x = - 5

given f(x) ± c , the value of c translates the graph vertically up/down by ± c

here c = - 6 , thus graph is shifted down by - 6

thus the vertex = (- 5, - 6)


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Which expression has a value of 8?<br> 8x (5-4)<br> (8 x 5) – 4<br> (8 x 5-4)<br> 8 x 5 - 4
fomenos
8x5-4 is equal to 8 if that means 8 times 5 minus 4
4 0
3 years ago
Three consecutive integers can be represented by the variable n, n+1 and n+2. If the sum of three consecutive integers is 57, wh
pashok25 [27]
You have some unknown integer n, and you know that adding this and the next two integers, n+1 and n+2, gives a total of 57.

This means

n+(n+1)+(n+2)=57

The task is to find all three unknown integers. Notice that if you know the value of n, then you pretty much know the value of the other three integers.

To find n, solve the equation above:

n+(n+1)+(n+2)=3n+3=57\implies 3n=54\implies n=\dfrac{54}3=18

So if 18 is the first integer, then others must be 19 and 20.
7 0
3 years ago
Read 2 more answers
help with this please
Ierofanga [76]

Answer:

see explanation

Step-by-step explanation:

Under a translation < 5, - 9 >

5 is added to the original x- coordinate and 9 is subtracted from the original y- coordinate, that is

A(1, 4 ) → A'(1 + 5, 4 - 9 ) → A'(6, - 5 )

B(2, - 2 ) → B'(2 + 5, - 2 - 9 ) → B'(7, - 11 )

C(- 3, 2 ) → C'(- 3 + 5, 2 - 9 ) → C'(2, - 7 )

7 0
3 years ago
I NEED THIS ANSWER ASAP(1000-???)=487​
lakkis [162]

Answer:

The answer is 513

Step-by-step explanation:

To get this answer you can subtract 487 from 1000 and then put the answer in the missing place!

-Hope this helps-

Bai~

5 0
3 years ago
Read 2 more answers
What is the equation of the line that passes through the points (5, 3) and (-3,-1)?
Liono4ka [1.6K]

Answer:

y=1/2x+1/2

m=1/2

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(5,3) and (-3,-1).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (5,3), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=5 and y1=3.

Also, let's call the second point you gave, (-3,-1), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-3 and y2=-1.

Now, just plug the numbers into the formula for m above, like this:

m=

-1 - 3 over

-3 - 5

or...

m=

-4 over

-8

or...

m=1/2

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=1/2x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(5,3). When x of the line is 5, y of the line must be 3.

(-3,-1). When x of the line is -3, y of the line must be -1.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=1/2x+b. b is what we want, the 1/2 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (5,3) and (-3,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(5,3). y=mx+b or 3=1/2 × 5+b, or solving for b: b=3-(1/2)(5). b=1/2.

(-3,-1). y=mx+b or -1=1/2 × -3+b, or solving for b: b=-1-(1/2)(-3). b=1/2.

See! In both cases we got the same value for b. And this completes our problem.

The equation of the line that passes through the points

(5,3) and (-3,-1)

is

y=1/2x+1/2

7 0
3 years ago
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