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3 years ago

6

A computer manufacturer is performing a quality check to make sure the computers’ sound cards are working correctly. The plant m

anager tested 1,000 computers on Monday and found that 4 had defective sound cards. What is the experimental probability of a computer having a bad sound card?

2 answers:

sergey [27]3 years ago

8 0

Answer:

The answer is :1/250

hope this helps!

Klio2033 [76]3 years ago

6 0

we need to find the probability of bad sound cards.

we are having 1000 computers so 1000 sound card will be there.

manager found that 4 sounds are defective out of 1000 sound cards.

$P(D)$ of defective sound cards= $n(D)/n(s)=4/1000=0.004$

we know that 1 is the total probability.out of 0.004 is the failure.

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Kazeer [188]

Answer:

$P(x\le 4\ or x> 10) = \frac{4}{7}$ or $P(x\le 4\ or x> 10) = 0.5714$

Step-by-step explanation:

Given

$x = \{1,2,3,4,5,6,7,8,9,10,11,12,13,14\}$

Required

Determine $P(x\le 4\ or x> 10)$

Because the events are independent, the probability can be solved using:

$P(A\ or\ B) = P(A) + P(B)$

So, we have:

$P(x\le 4\ or x> 10) = P(x \le 4) + P(x > 10)$

When $x \le 4$ , we have: $x = \{1,2,3,4\}$

So:

$P(x \le 4) = \frac{4}{14}$

Also:

When $x > 10$ , we have: $x = \{11,12,13,14\}$

So:

$P(x>10) =\frac{4}{14}$

$P(x\le 4\ or x> 10) = P(x \le 4) + P(x > 10)$ becomes

$P(x\le 4\ or x> 10) = \frac{4}{14} + \frac{4}{14}$

$P(x\le 4\ or x> 10) = \frac{4+4}{14}$

$P(x\le 4\ or x> 10) = \frac{8}{14}$

$P(x\le 4\ or x> 10) = \frac{4}{7}$

$P(x\le 4\ or x> 10) = 0.5714$

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3 years ago

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weqwewe [10]

Answer:81/m^7(D)

Step-by-step explanation:

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81/m^7

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3 years ago

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3 years ago

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Sarah multiplied 4.16 and 1.83, as shown. But she forgot to put a decimal point in the answer. Complete the sentence below.

Gre4nikov [31]

Answer: The correct answer should be 7.6128

If you do the problem correctly, you will get an answer of 7.6128. This is because there are 4 decimals places in the numbers that are being multiplied. This means that there will be 4 decimal places in the answer. If you have her work, we can find the mistake. It is probably that she counted the wrong number of places.

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4 years ago

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11. Mr Lee bought a second hand car for

Marrrta [24]

Answer :

Depends on the rate compound interest is accrued. See answers.

Step-by-step explanation:

We need the compound interest formula which is:

$A = P (1+\frac{r}{n} )^{nt}$

A = final amount

P = initial principal balance

r = interest rate

n = number of times interest applied per time period

t = number of time periods elapsed

It doesn't say how frequently the interest is compounded, so we will do monthly, quarterly, and yearly.

MONTHLY

So we know the car costs $25,480 and he made a down payment of $10,000. By subtracting the down payment from the purchase price we find the loan amount.

$25,480 - $10,000 = $15,480

P = 15,480

r = 4.75% = .0475

n = 12 (12 months in a year)

t = 2

Plug everything into the compound interest formula.

$A = P (1+\frac{r}{n} )^{nt}$

$A = 15480(1+\frac{.0475}{12})^{12*2}$

$A = 15480(1+\frac{.0475}{12})^{24}$

$A = 15480(1+.00396)^{24}$

$A = 15480(1.00396)^{24}$

$A = 15480*1.0992$

$A = $17016.14$

Mr. Lee paid $17,016.14 when the bill came due at 2 years with interest compounded monthly.

QUARTERLY

P = 15,480

r = 4.75% = .0475

n = 4 (4 quarters in a year)

t = 2

$A = P (1+\frac{r}{n} )^{nt}$

$A = 15480(1+\frac{.0475}{4})^{4*2}$

$A = 15480(1+\frac{.0475}{4})^{8}$

$A = 15480(1+.0119})^{8}$

$A = 15480(1.0119)^{8}$

$A = 15480*1.099$

$A = 15480(1.099)$

$A = 17013.20$

Mr. Lee paid $17,013.20 when the bill came due at 2 years with interest compounded quarterly.

YEARLY

P = 15,480

r = 4.75% = .0475

n = 1

t = 2

$A = P (1+\frac{r}{n} )^{nt}$

$A = 15480(1+\frac{.0475}{1})^{1*2}$

$A = 15480(1+\frac{.0475}{12})^{2}$

$A = 15480(1+.0475})^{2}$

$A = 15480(1.0475)^{2}$

$A = 15480*1.0973$

$A = 16985.53$

Mr. Lee paid $16,985.53 when the bill came due at 2 years with interest compounded yearly.

4 0

4 years ago