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3 years ago

12

Please help! Must get done ASAP!!! ^^

2 answers:

pentagon [3]3 years ago

3 0

Answer:

No

No

Yes

Yes

Step-by-step explanation:

Try it.

lara [203]3 years ago

3 0

Answer: 1st: No, 2nd: No, 3rd: Yes, 4th: Yes

Step-by-step explanation: You only flip the inequality when you divide a negative number on both sides. The only reason why you would divide would be to get the variable by itself - in this case the coefficient would need to be negative. That only applies to the third and 4th equations.

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Consider the sequence: 12, 17, 22, ... , ... , .... What is the 405th term of this sequence?

Mice21 [21]

A_n= a₁+(n-1)d

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n terms

d distance between each value

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7 0

3 years ago

Read 2 more answers

Marjorie consumed 1.5 gallons of water in one day. How many milliliters are equal to 1.5 gallons, if 1 liter = 1,000 milliliters

alekssr [168]

1.5 * 3.785 * 1000 milliliters

8 0

3 years ago

Match each set of numbers with their least common multiple.

mylen [45]

Answer:

27, 12, and 36 = 108

22 and 4 = 44

14 and 12 = 84

25 and 8 =200

9, 8, and 7 = 504

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Step-by-step explanation: You are welcome.

5 0

3 years ago

Do the ratios 10/8 and 16/20 form a proportion<br><br> Yes or no?

ziro4ka [17]

Answer:

No. Reduce 10/8 by dividing by 2. 10/8= 5, 8/2= 4. 10/8= 5/4. Reduce 16/20 by dividing by 4. 16/4= 4 , 20/4= 5. 16/20= 4/5.

6 0

3 years ago

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by <em>b</em> :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since <em>a/b</em> < <em>c/d</em>, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by <em>b/d</em> to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) < <em>c/d</em>.

For the other side, you can do something similar and divide through everything by <em>d</em> :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and <em>a/b</em> < <em>c/d</em> tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) > <em>a/b</em>.

Then together we get the desired inequality.

5 0

3 years ago