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iragen [17]
3 years ago
7

Gloria needs 2/5 yard of ribbons to make each bow. Write and solve an equation to find how any bows she can make with 8 yards of

ribbon
Mathematics
1 answer:
NeTakaya3 years ago
7 0

Answer:

Equation : \frac{2}{5}r=8

She can make 20 bows with 8 yards of ribbon

Step-by-step explanation:

Gloria needs 2/5 yard of ribbons to make each bow.

Length of 1 bow =\frac{2}{5} yards

Let r be the no. of bows made

So, Length of r bows = \frac{2}{5}r

We are given that  she can make r bows with 8 yards of ribbon

So, Equation : \frac{2}{5}r=8

r=\frac{8 \times 5}{2}

r=20

Hence She can make 20 bows with 8 yards of ribbon

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Answer:

Y=1.88x

Step-by-step explanation:

x1=2 x2=3, y1=3.76 y2=5.64

(2, 3.76) (3, 5.64)

m(slope) =5.64-3.76/3-2

m=1.88

y-3.76=1.88(x-2)

y-3.76=1.88x-3.76

Y=1.88x

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3 years ago
What is the equation of the line that passes through the point (3,-5)(3,−5) and has a slope of 0?
bearhunter [10]

Answer:

y=x-5

Step-by-step explanation:

y=mx+b

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3 years ago
Which equation is modeled by the graph? Using the equation, about how many more cars are in the deck at 9:00 a.m. than at 8:30 a
omeli [17]
The correct answer is Choice A.

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To find the slope, we can use the following two points (0, 50) and (20, 110). This will give a slope of 3.

Put the 50 and 3 together and you will have the equation:
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3 years ago
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Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and
zloy xaker [14]

Answer:

(0,0)   (4000,0) and (500,79)

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW

\frac{dW}{dt} = -0.02W + 0.00004RW

To solve this, we first equate \frac{dR}{dt} and \frac{dW}{dt} to 0.

So, we have:

0.09R(1 - 0.00025R) - 0.001RW = 0

-0.02W + 0.00004RW = 0

Factor out R in 0.09R(1 - 0.00025R) - 0.001RW = 0

R(0.09(1 - 0.00025R) - 0.001W) = 0

Split

R = 0   or 0.09(1 - 0.00025R) - 0.001W = 0

R = 0   or  0.09 - 2.25 * 10^{-5}R - 0.001W = 0

Factor out W in -0.02W + 0.00004RW = 0

W(-0.02 + 0.00004R) = 0

Split

W = 0 or -0.02 + 0.00004R = 0

Solve for R

-0.02 + 0.00004R = 0

0.00004R = 0.02

Make R the subject

R = \frac{0.02}{0.00004}

R = 500

When R = 500, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0

0.09 -0.01125 - 0.001W = 0

0.07875 - 0.001W = 0

Collect like terms

- 0.001W = -0.07875

Solve for W

W = \frac{-0.07875}{ - 0.001}

W = 78.75

W \approx 79

(R,W) \to (500,79)

When W = 0, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0

0.09 - 2.25 * 10^{-5}R = 0

Collect like terms

- 2.25 * 10^{-5}R = -0.09

Solve for R

R = \frac{-0.09}{- 2.25 * 10^{-5}}

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(R,W) \to (4000,0)

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-0.02W + 0.00004W*0 = 0

-0.02W + 0 = 0

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(R,W) \to (0,0)

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