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iragen [17]
3 years ago
7

Gloria needs 2/5 yard of ribbons to make each bow. Write and solve an equation to find how any bows she can make with 8 yards of

ribbon
Mathematics
1 answer:
NeTakaya3 years ago
7 0

Answer:

Equation : \frac{2}{5}r=8

She can make 20 bows with 8 yards of ribbon

Step-by-step explanation:

Gloria needs 2/5 yard of ribbons to make each bow.

Length of 1 bow =\frac{2}{5} yards

Let r be the no. of bows made

So, Length of r bows = \frac{2}{5}r

We are given that  she can make r bows with 8 yards of ribbon

So, Equation : \frac{2}{5}r=8

r=\frac{8 \times 5}{2}

r=20

Hence She can make 20 bows with 8 yards of ribbon

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Mary Ann needs 3/7 cup of sugar to bake a cake she has 3/5 cup does she have enough to bake the cake yes or no
IrinaVladis [17]

Answer:

Mary Ann does have enough sugar

Step-by-step explanation:

3/5 is greater than 3/7 which means that she does have enough sugar. This is because the denominator 5 is smaller than the denominator 7, and since they have the same numerator, the fraction with the smaller denominator is greater.

5 0
2 years ago
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I WILL GIVE YOU BRAINLIEST, AND 30 POINTS SO PLEASE HELP ME, IT'S URGENT!
Keith_Richards [23]
A is the right answer.
5 0
3 years ago
What are the vertical and horizontal asymptotes for the function f(x)=<br> 3x2/x2-4
Alecsey [184]

Answer:  f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.

Step-by-step explanation:

Given function: f(x)=\dfrac{3x^2}{x^2-4}

The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.

i.e. x^2-4=0\Rightarrow\ x^2=4\Rightarrow\ x=\pm2

Hence, f(x) will have vertical asymptotes at x=-2 and x=2.

To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.

So, the graph will horizontal asymptote at y=\dfrac{\text{Coefficient of }x^2\text{ in numerator}}{\text{Coefficient of }x^2\text{ in denominator}}

i.e. y=\dfrac{3}{1}=3

Hence, f(x) will have horizontal asymptote at y=3.

3 0
3 years ago
Raíz cuadrada de 864
marshall27 [118]

Raíz cuadrada de 864

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

The general equation of ellipse is given as, x2a2+y2b2=1 x 2 a 2 + y 2 b 2 = 1 , where, a is length of semi-major axis and b is length of semi-minor axis.

centro: (0,0)

focus : (0, -√28) , (0, √28)

eje conjugado = 2√3

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

de los focos podemos obtener que: √28

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b = √3

podemos utilizar la siguiente fórmula para obtener a:

si despejamos a en la ecuación obtenemos lo siguiente:

ahora podemos sustituir los valores:

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

si graficamos la hipérbola, queda como en el documento adjunto.

To learn more hipérbola

Visit : brainly.com/question/24223341

#SPJ9

8 0
1 year ago
The owner of a bookstore orders 32 copies of a book for $12.34 each.
makvit [3.9K]
If you are buying 32 copies of a book and each copy costs 12.34 you should multiply $12.34 by the amount of copies being bought in this case 32 so
12.34x32= 394.88
The total cost of the books is $394.88
5 0
3 years ago
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