Answer:
Possible values of dimensions are (24,16,2) or (24,8,4)
Step-by-step explanation:
We are given the volume of the Cuboid and length . We are required to find the possible values of width and height from this information.
Let us say that the width is x and height is y
Length = 24
Volume of a cuboid = length * width * height
Volume = 768
768=24*x*y

xy=32
Now the possible factors of 32
32=1*32 ( Which shall not be taken into consideration as length is already given as 24 and width or height can not be more length)
32=2*16
32=4*8
Hence the possible values width are 8, 16 and that of height 4 and 2
Hence the possible values of dimensions are (24,16,2) or (24,8,4)
Let the width be x
The length would be 2x-5
So, 2(x+2x-5)=80
3x-5=40
3x=45
x=15.
So the width is 15 and the length would be 25.
For this you'll want to draw out Triangle ABC and label it as the problem gives you.
Draw a similar triangle to the first one you drew and label it the exact same way as "ABC" and then match the measurement "AB" to "HJ".
Hope this helps.
Answer:
0.321 hectometres
0.0321 kilometres
32.1 metre
Step-by-step explanation: