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I would assume it's the area of both the sidewalk and pool combined (79ft x 49ft = 3,871) minus the area of the pool alone (75ft x 45ft = 3,375). The area of the sidewalk would then be 496 ft
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Use pythagorean theorem
a^2+b^2=c^2
first find the difference of between the 2 points to find the legnth of the legs
distance between 2 and 5=3
distance between 3 and 8=5 so
3^2+5^2=c^2
9+25=c^2
34=c^2
√34=c
the ligit formula is
a^2+b^2=c^2
first find the difference of between the 2 points to find the legnth of the legs
distance between 2 and 5=3
distance between 3 and 8=5 so
3^2+5^2=c^2
9+25=c^2
34=c^2
√34=c
the ligit formula is