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3 years ago

cuboid of length 24cm and volume 768cm^3 the width and hight are not equal.give a pair of possible values for their length.

Mathematics

1 answer:

Brilliant_brown [7]3 years ago

3 0

Answer:

Possible values of dimensions are (24,16,2) or (24,8,4)

Step-by-step explanation:

We are given the volume of the Cuboid and length . We are required to find the possible values of width and height from this information.

Let us say that the width is x and height is y

Length = 24

Volume of a cuboid = length * width * height

Volume = 768

768=24*x*y

$xy=\frac{768}{24}\\xy=32\\$

xy=32

Now the possible factors of 32

32=1*32 ( Which shall not be taken into consideration as length is already given as 24 and width or height can not be more length)

32=2*16

32=4*8

Hence the possible values width are 8, 16 and that of height 4 and 2

Hence the possible values of dimensions are (24,16,2) or (24,8,4)

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// Input value is usernum.
// This code snippet sums 1 + 3 + 5 + ... + usernum
// The answer is stored in the variable summedvalue.

N = (int) (usernum+1)/2; // maximum number of integers to be summed
int *v = malloc(N*sizeof(int)); // allocate storage for array v

// Calculate the number of loop counts and assign array v..
count = 0;
k = 1;
while (1) {
if (k>usernum) { // do not extend v beyond usernum
break;
}
v(count) = k; // assign an odd integer to v, including usenum
count++;
k += 2; // k is an odd number
if k>usernum { // handle usernum as odd or even
k = usernum;
}
}
n = count; // the size of array v.

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summedvalue = 0; // initialize summedvalue
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3 years ago

cuboid of length 24cm and volume 768cm^3 the width and hight are not equal.give a pair of possible values for their length.​

cuboid of length 24cm and volume 768cm^3 the width and hight are not equal.give a pair of possible values for their length.