A cylindrical oil tank 8 ft deep holds 620 gallons when filled to capacity. How many gallons remain in the tank when the depth o
f oil is 3 and one half ft.
2 answers:
Answer:
271.25
Step-by-step explanation:
8=620
3 1/2=x
620×7/2=8x
2170=8x
x=2170/8
x=271.25
Answer:
271.25 gal
Step-by-step explanation:
Assuming the tank is oriented so that the quantity of oil is proportional to depth, the amount remaining is ...
(3 1/2 ft)/(8 ft) × (620 gal) = 271 1/4 gal
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