A cylindrical oil tank 8 ft deep holds 620 gallons when filled to capacity. How many gallons remain in the tank when the depth o
f oil is 3 and one half ft.
2 answers:
Answer:
271.25
Step-by-step explanation:
8=620
3 1/2=x
620×7/2=8x
2170=8x
x=2170/8
x=271.25
Answer:
271.25 gal
Step-by-step explanation:
Assuming the tank is oriented so that the quantity of oil is proportional to depth, the amount remaining is ...
(3 1/2 ft)/(8 ft) × (620 gal) = 271 1/4 gal
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Answer:
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207.35</em></u></h2>
Step-by-step explanation:
2 14/16. .........................That's the answer
Step-by-step explanation:
True...it was Answer but not in always
9 x 8 = 72
155 - 72 = 83
83 divided by 6 =13.8
So he has to make at least 14 deliveries in order to reach his goal.