Ask question

Ask question

All categories

2 years ago

6

Lucy is shipping 5 boxes that all weigh the same, and 1 envelope that weighs 7.5 pounds. The total weight of the shipment is 65

pounds. What is the weight, in pounds, of each box?
A. 5.5

B .11.5

C. 14.5

D. 20.5

2 answers:

alexgriva [62]2 years ago

7 0

Answer is 11.5

Total weight of the shipment is 65, and 1 envelope weight 7.5 that’s means
65-7.5= 57.5

As we are looking for each box weight in pounds so you divided 57.5/5 =11.50

Hope this helps!

Dovator [93]2 years ago

6 0

Initial weight= 65 lbs total

STEP 1
Subtract weight of envelope from total weight

65 - 7.5= 57.5 lbs for 5 boxes

STEP 2
Divide remaining weight equally into 5 parts (5 boxes of equal weight)

57.5 ÷ 5= 11.5 lbs per box

ANSWER: Each box weighs (B) 11.5 pounds.

Hope this helps! :)

You might be interested in

Which linear equation best describes the relationship between x and y?

Sergio [31]

Slope = 2/3
y = mx + b
6 = 2/3(3) + b so b = 4

equation
y = 2/3x + 4
3y = 2x + 12

answer is c.3y = 2x + 12

6 0

3 years ago

3m - 3(m+8) > 3m<br><br><br> (Teacher didn't go over this hopefully I can get an explanation)

zhuklara [117]

Alrighty!

*Note the ">" sign is similar to the "=" sign.

3m - 3(3m + 8) > 3m
3m - 6m + 24 > 3m (distribute)
-3m + 24 > 3m (combine like terms)
24 > 6m (Compute/simplify)
8 > m

Makes sense?

8 0

3 years ago

X * 4 = x + 1.5 = help plzzzzzz!

Leona [35]

Answer:

5

Step-by-step explanation:

x × 4 = x + 15

4x = x + 15

-x -x

3x= 15

-- --

3 3

x = 5

// have a great day //

3 0

2 years ago

Read 2 more answers

50 PTS ANSWER ALL <3333333

11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

${h}^{2} = {6}^{2} + {8}^{2}$

${h}^{2} = 36+ 64$

${h}^{2} = 100$

$h = \sqrt{100}$

$h = 10cm$

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

${l}^{2} + {33}^{2} = {55}^{2}$

${l}^{2} = {55}^{2} - {33}^{2}$

${l}^{2} = 1936$

$l = \sqrt{1936}$

$l = 44cm$

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values to get,

$d=\sqrt{( - 1-2)^2+(3- - 1)^2}$

$d=\sqrt{( - 3)^2+(4)^2}$

$d=\sqrt{9+16}$

$d=\sqrt{25}$

$d = 5$

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

$d=\sqrt{( - 3-2)^2+( - 3- 2)^2}$

$d=\sqrt{( - 5)^2+( - 5)^2}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

$d=5\sqrt{2}$

Answer: D

8 0

2 years ago

Read 2 more answers

PLEASE ANSWER QUICKLY

jenyasd209 [6]

Answer:

It should be D because I have done that a couple days ago

6 0

2 years ago