Eliminate the parameter t to find a cartesian equation for x=t^2 y=2+10t

1 answer:

3 0

Hello :
$\left \{ {{x= t^{2} }...(1) \atop {y=2+ 10t }...(2)} \right.$
by(1) :
$t = \frac{y-2}{10}$
subsct in (2) :
$x = ( \frac{y-2}{10} )^{2}$ ....(cartesian equation )

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