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Eduardwww [97]
3 years ago
11

Fifteen times the square of a non-zero number is equal to 15 times the number

Mathematics
2 answers:
scoundrel [369]3 years ago
6 0
If were translating it the the answer is 15*x^2 = 15x but if were not then i don't know what to do here. Hope this helps!
defon3 years ago
5 0
15·x²=15·x so 
x²=x 
x·x=x  with x≠0 than x must be 1 
x=1
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Can somebody plz help me with this question plz someone I swear I need help asap
boyakko [2]

[ Answer ]

\boxed{270 \ Yards^{2} }

[ Explanation ]

  • Find Area Of Rectangle That Measures 18 Feet Long And 15 Feet Wide

-----------------------------------

Area = Base · Height

Base - 15

Height - 18

  • Insert Numbers Into Equation

15 · 18

  • Solve

15 · 18 = 270

  • Answer

270 Yards^{2}

\boxed{[ \ Eclipsed \ ]}

3 0
3 years ago
How to expand (2x+1)(x+1)
Inga [223]
(2x+1)(x+1)
Now multiply 2x to both x and +1
2x^2+2x
Do the same with 1 multiply it to x and +1
2x^2+2x +x+1
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8 0
3 years ago
Read 2 more answers
Suppose you deposit 2500 in a savings account that pays you 5% interest per year A. How many years will it take for you to doubl
zhannawk [14.2K]

Answer: I don’t get it

Step-by-step explanation:

8,000 or 08,080?

8 0
3 years ago
Find the vertex and zeros of the following function f(x)=x^2-6x-7
elena-s [515]

Try this solution:

Step-by-step explanation:

1) for zeros of the function: x²-6x-7=0; ⇒ x₁=7; x₂= -1.

2) for the vertex of the function: x₀= -b/2a, where a;b;c - numbers from ax²+bx+c=0 (from x²-6x-7=0).

x₀=6/2=3;

y₀= (4ac-b²)/4a; ⇒ y₀= -16.

It means, the coordinates of the vertex are (3;-16).

6 0
3 years ago
Please assist me with #5, 6, 7, 8​
Leona [35]

Answer:

5a. -0.4 m/s²

5b. 290 m

6. 12.9 s

7. 100 s

8. 17.2 km/hr

Step-by-step explanation:

5. "While approaching a police officer parked in the median, you accelerate uniformly from 31 m/s to 27 m/s in a time of 10 s.

a. What is your acceleration?

b. How far do you travel in that time?"

Given:

v₀ = 31 m/s

v = 27 m/s

t = 10 s

Find: a and Δx

v = at + v₀

(27 m/s) = a (10 s) + (31 m/s)

a = -0.4 m/s²

Δx = ½ (v + v₀) t

Δx = ½ (27 m/s + 31 m/s) (10 s)

Δx = 290 m

6. "If a pronghorn antelope accelerates from rest in a straight line with a constant acceleration of 1.7 m/s², how long does it take for the antelope to reach a speed of 22 m/s?"

Given:

v₀ = 0 m/s

v = 22 m/s

a = 1.7 m/s²

Find: t

v = at + v₀

(22 m/s) = (1.7 m/s²) t + (0 m/s)

t = 12.9 s

7. "A 1200 kg airplane starts from rest and moves forward with a constant acceleration of 5 m/s² along a runway that is 250 m long. How long does it take the plane to travel the 250 m?"

Given:

v₀ = 0 m/s

a = 5 m/s²

Δx = 250 m

Find: t

Δx = v₀ t + ½ at²

(250 m) = (0 m/s) t + ½ (5 m/s²) t²

t = 100 s

8. "During a marathon, a runner runs the first 10 km in 0.58 hours, the next 10 km in 0.54 hours and the last 10 km in 0.62 hours.  What is the average speed of the runner during that marathon?"

This isn't a constant acceleration problem, so there's no need for a chart.

Average speed = total distance / total time

v = (10 km + 10 km + 10 km) / (0.58 hr + 0.54 hr + 0.62 hr)

v = 30 km / 1.74 hr

v = 17.2 km/hr

3 0
3 years ago
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