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andre [41]
3 years ago
5

How do you write the algebraic notation when the scale factor is 3 ​

Mathematics
1 answer:
Alja [10]3 years ago
3 0

Answer:

(x,y) = (3x,3y)

Step-by-step explanation:

You might be interested in
Is (the fraction in the photo) rational or irrational?
love history [14]

Answer:

Irrational

Step-by-step explanation:

The square root of 2 is an irrational number as it is: ≈ 1.41. When you divide the square root of 2 by 3, it's still irrational: 0.47140452...

3 0
3 years ago
The quotient of a number and 8 is 4. Write an algebraic equation for the word sentence.__________________-
Papessa [141]

Answer:

(x/8) = 4

Step-by-step explanation:

7 0
3 years ago
Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. Which statement is true? A) Only x = –7 is an extraneous solution.
11111nata11111 [884]

Answer:

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

\sqrt{11-2x}=\sqrt{x^{2}+4x+4}

we know that

two possible solutions are x=-7 and x=1

<u><em>Verify each solution</em></u>

Substitute each value of x in the expression above and interpret the results

1) For x=-7

\sqrt{11-2(-7)}=\sqrt{-7^{2}+4(-7)+4}

\sqrt{25}=\sqrt{25}

5=5 ----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1

\sqrt{11-2(1)}=\sqrt{1^{2}+4(1)+4}

\sqrt{9}=\sqrt{9}

3=3 ----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

7 0
3 years ago
Read 2 more answers
Fill in the missing expression
padilas [110]

Answer:

The complete table is:

[ 5a ]           +    [ a + 3 ]      +    [ 4a ]     =    [ 10a + 3 ]

  +                         +                    +                    +

[ 2b ]          +     [ 4 + a ]      +     [ -a  ]     =    [  2b + 4 ]

  +                       +                     +                    +

[ 2a ]          +    [ a + 1 ]       +   [  -3a  ]    =   [     1      ]

  =                      =                     =                     =

[ 7a + 2b ]  +   [ 3a + 8 ]    +     [   0   ]    =   [10a + 2b + 8 ]

Explanation:

You can determine the content of each box by subtraction, running the rows and the columns.

The expressions are:

[ 5a ]  +    [          ]   +    [ 4a ]     =    [ 10a + 3 ]

  +                +                +                    +

[ 2b ]  +   [ 4 + a ]   +     [      ]     =    [              ]

  +              +                   +                    +

[      ]   +   [         ]   +      [  -3a  ]  =   [     1      ]

  =               =                   =                   =

[      ]  +   [ 3a + 8 ]  +  [         ]    =   [10a + 2b + 8 ]

<u>1. First row:</u>

[ 5a ]  +    [          ]   +    [ 4a ]     =    [ 10a + 3 ]

[      ] = [10a+ 3]  - [ 4a ] - [ 5a ] = 10a - 4a - 5a + 3 = a + 3

<u>2. Second colum:</u>

[ a + 3 ] + [ 4 + a ] + [       ] =  [ 3a + 8 ]

[        ] = [ 3a + 8 ] - [ a + 3 ] - [ 4 + a ] = 3a - a  + a  + 8 - 4 - 3 = a + 1

So far, you have completed this:

[ 5a ]  +    [ a + 3 ]   +    [ 4a ]     =    [ 10a + 3 ]

  +                +                +                    +

[ 2b ]  +   [ 4 + a ]   +     [      ]     =    [              ]

  +              +                   +                    +

[      ]   +   [ a + 1 ]   +     [  -3a  ]  =   [     1      ]

  =               =                   =                   =

[      ]  +   [ 3a + 8 ]  +  [         ]    =   [10a + 2b + 8 ]

<u></u>

<u>3. Complete the row 3:</u>

<u></u>

     [      ]   +   [ a + 1 ]   +      [  -3a  ]  =   [     1      ]

    [      ]   =    [     1      ]   -   [ a + 1 ]   -    [  -3a  ]  = - a + 3a + 1 - 1 = 2a

So far, you have completed this:

[ 5a ]  +    [ a + 3 ]   +    [ 4a ]     =    [ 10a + 3 ]

  +                +                +                    +

[ 2b ]  +   [ 4 + a ]   +     [      ]     =    [              ]

  +              +                   +                    +

[   2a   ]   +   [ a + 1 ]   +     [  -3a  ]  =   [     1      ]

  =               =                   =                   =

[      ]  +   [ 3a + 8 ]  +  [         ]    =   [10a + 2b + 8 ]

<u></u>

<u>4. Complete the fourth column:</u>

[ 10a + 3 ] + [    ] + [   1   ] = [10a + 2b + 8 ]

[    ] = 10a + 2b + 8 - 10a - 3 - 1 = 2b + 4

So far, this is the results:

[ 5a ]  +    [ a + 3 ]   +    [ 4a ]     =    [ 10a + 3 ]

  +                +                +                    +

[ 2b ]  +   [ 4 + a ]   +     [      ]     =    [  2b + 4 ]

  +              +                   +                    +

[   2a   ]   +   [ a + 1 ]   +     [  -3a  ]  =   [     1      ]

  =               =                   =                   =

[      ]  +   [ 3a + 8 ]  +  [         ]    =   [10a + 2b + 8 ]

<u>5. Complete the second row:</u>

[ 2b ]  +   [ 4 + a ]   +     [      ]     =    [  2b + 4 ]

 [      ]   =   [  2b + 4 ] - [ 2b ]  -   [ 4 + a ]  = 2b - 2b + 4 - 4 - a = - a

So far:

[ 5a ]  +    [ a + 3 ]      +    [ 4a ]     =    [ 10a + 3 ]

  +                +                    +                    +

[ 2b ]  +   [ 4 + a ]      +     [ -a  ]     =    [  2b + 4 ]

  +               +                     +                    +

[   2a   ]   +   [ a + 1 ]   +   [  -3a  ]  =   [     1      ]

  =               =                    =                   =

[      ]  +   [ 3a + 8 ]  +     [         ]    =   [10a + 2b + 8 ]

<u>6. Complete the first colum:</u>

[ 5a ] + [ 2b ] + [2a ] = [   ]

[   ] = [ 7a + 2b ]

So far:

[ 5a ]           +    [ a + 3 ]      +    [ 4a ]     =    [ 10a + 3 ]

  +                         +                    +                    +

[ 2b ]           +   [ 4 + a ]      +     [ -a  ]     =    [  2b + 4 ]

  +                       +                     +                    +

[ 2a ]          +   [ a + 1 ]       +   [  -3a  ]    =   [     1      ]

  =                      =                     =                    =

[ 7a + 2b ]  +   [ 3a + 8 ]   +     [         ]    =   [10a + 2b + 8 ]

<u>7. Complete the last row:</u>

[ 7a + 2b ]  +   [ 3a + 8 ]   +     [         ]    =   [10a + 2b + 8 ]

[         ]    =   [10a + 2b + 8 ] - [ 7a + 2b ] - [ 3a + 8 ] = 0

The complete table is:

[ 5a ]           +    [ a + 3 ]      +    [ 4a ]     =    [ 10a + 3 ]

  +                         +                    +                    +

[ 2b ]           +   [ 4 + a ]      +     [ -a  ]     =    [  2b + 4 ]

  +                       +                     +                    +

[ 2a ]          +   [ a + 1 ]       +     [ -3a  ]    =   [     1      ]

  =                      =                     =                     =

[ 7a + 2b ]  +   [ 3a + 8 ]    +     [   0  ]     =   [10a + 2b + 8 ]

5 0
3 years ago
Add<br>3×+8y-12zand5x-7y+15z<br>help meee<br>​
inn [45]

3x+5x+12z+15z+8y+7y

8x+17z+15y

4 0
3 years ago
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