Based on the given data; the table represent an inverse variation and the equation that model the data in the table is y = 8/x
<h3>Variation</h3>
y = k × x
4 = k × 2
4 = 2k
k = 4/2
k = 2
when y = 2 and x = 4
y = k × x
= 2 × 4
y = 8
y = k/x
4 = k / 2
8 = k
when y = 2 and x = 4
y = k/x
2 = k/4
2 × 4 = k
k = 8
So,
y = k/x
y = 8/x
Learn more about variation:
brainly.com/question/6499629
#SPJ1
Answer:
Step-by-step explanation:
There is <em>one-and-a-half</em> <em>hour</em> in <em>ninety</em><em> </em><em>minutes</em>,<em> </em>so multiply 6 by 15 to get 90, then whatever is done to the bottom is also done to the top, so you <em>square</em> 6 to get 36.
I am joyous to assist you anytime.
Given:
The graph of a function and a blue line.
To find:
The correct name for the blue line.
Solution:
Domain: It is the set of inputs. These are the x-values for which the function is defined.
Range: It is the set of outputs. These are the y-values for the function.
Asymptote: The function approaches to a line as x approaches to -∞ or ∞ but not intersect the line, then the line is known as asymptote.
y-intercept: It is the intersection point of the function and the y-axis.
From the given graph it is clear that the function approaches to the blue line as x approaches to -∞ but not intersect the blue line.
So, the blue line is an asymptote of the function.
Look at the graph shown below the blue line represents an asymptote of the graph.
Y=mx+b
m=slope
b=yint
find slope
slope between (x1,y1) and (x2,y2) is (y1-y2)/(x1-x2)
given
(-3,5) and (1,1)
slope=(5-1)/(-3-1)=4/-4=-1
y=-1x+b
find b
when x=1, then y=1
1=-1(1)+b
1=-1+b
add 1
2=b
y=-x+2
Step-by-step explanation:
<u>y</u> - <u>1</u> = <u>-</u><u>3</u>
x - 0 2
2y - 2 = -3x
2y = -3x + 2
