Answer:
The base is 19.5.
Step-by-step explanation:
The given question is, "The perimeter of a rectangle is 58 and its base exceeds its width by 10, how long is the base?"
Perimeter = 58
Base, l = 10+b
The perimeter of a rectangle is :
P = 2(l+b)
58 = 2(10+b+b)
29 = (10+2b)
29-10 = 2b
19 = 2b
b = 9.5
Base, l = 10 + 9.5
= 19.5
Hence, the base is 19.5.
Step 1. Set up long division
_______
7| 1 9 8 6
Step 2. <span>Calculate 19 ÷ 7, which is 2 with a remainder of 5.
2
</span> _______
7| 1 9 8 6
1 4
_________
5
Step 3. Bring down 8, so that 58 is large enough to be divided by 7.
2
_______
7| 1 9 8 6
1 4
_________
5 8
Step 4. <span>Calculate 58 ÷ 7, which is 8 with a remainder of 2.
</span> 2 8
_______
7| 1 9 8 6
1 4
_________
5 8
5 6
_________
2
Step 5. <span>Bring down 6, so that 26 is large enough to be divided by 7.
</span> 2 8
_______
7| 1 9 8 6
1 4
_________
5 8
5 6
_______
2 6
Step 6. Calculate 26 ÷ 7, which is 3 with a remainder of 5.
2 8 3
_______
7| 1 9 8 6
1 4
_________
5 8
5 6
_______
2 6
2 1
______
5
Step 7. <span>Therefore, 1986 ÷ 7 = 283 with a remainder of 5.
823 With a remainder of 5
Done!
</span><span>Decimal Form If Needed: 283.714286</span>
The answer is y=-2/3x+3 :)
Answer:
The first one
Step-by-step explanation:
2y + 4x = -5
2y = -5 - 4x
y = - (5/2) - 2x
I believe its C. because you have to solve for x.
