Question

Hurryyyyy Dndixnxjdjdjddjjdjdudjddj

Answer 1

∛125x^10y^13 + ∛27x^10y^13

= 5x^3y^4 ∛xy + 3x^3y^4 ∛xy

= 8x^3y^4 ∛xy

Answer is A. 8x^3y^4 ∛xy

Answer 2

Answer:

$\large\boxed{8x^3y^4\sqrt[3]{xy}}$

Step-by-step explanation:

$\sqrt[3]{125x^{10}y^{13}}+\sqrt[3]{27x^{10}y^{13}}\qquad\text{use}\ \sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}\\\\=\sqrt[3]{125}\cdot\sqrt[3]{x^{10}y^{13}}+\sqrt[3]{27}\cdot\sqrt[3]{x^{10}y^{13}}\\\\=5\sqrt[3]{x^{10}y^{13}}+3\sqrt[3]{x^{10}y^{13}}\\\\=8\sqrt[3]{x^{10}y^{13}}\\\\=8\sqrt[3]{x^{3+3+3+1}y^{3+3+3+3+1}}\qquad\text{use}\ a^na^m=a^{n+m}\\\\=8\sqrt[3]{x^3x^3x^3xy^3y^3y^3y}\qquad\text{use}\ \sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}$

$=8\sqrt[3]{x^3}\cdot\sqrt[3]{x^3}\cdot\sqrt[3]{x^3}\cdot\sqrt[3]{y^3}\cdot\sqrt[3]{y^3}\cdot\sqrt[3]{y^3}\cdot\sqrt[3]{y^3}\cdot\sqrt[3]{xy}\qquad\text{use}\ \sqrt[n]{a^n}=a\\\\=8xxxyyyy\sqrt[3]{xy}\\\\=8x^3y^4\sqrt[3]{xy}$