To find the circumference, you will use the formula for finding circumference of a circle.
I used the true value of pi for the calculations.
C = pi x d
pi x 27.13
C = 85.77mm
C is 27/40. If you add it to 1/8 and simplify, you get 4/5.
One revolution is completed when a fixed point on the wheel travels a distance equal to the circumference of the wheel, which is 2π (13 cm) = 26π cm.
So we have
1 rev = 26π cm
1 rev = 2π rad
1 min = 60 s
(a) The angular velocity of the wheel is
(35 rev/min) * (2π rad/rev) * (1/60 min/s) = 7π/6 rad/s
or approximately 3.665 rad/s.
(b) The linear velocity is
(35 rev/min) * (26π cm/rev) * (1/60 min/s) = 91π/6 cm/s
or roughly 47.648 cm/s.
Answer:
third option
Step-by-step explanation:
Given
3 ![\left[\begin{array}{ccc}-2&5\\1&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%265%5C%5C1%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Multiply each element in the matrix by 3
= ![\left[\begin{array}{ccc}3(-2)&3(5)\\3(1)&3(0)\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%28-2%29%263%285%29%5C%5C3%281%29%263%280%29%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}-6&15\\3&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%2615%5C%5C3%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Y=-x+1 is the correct slope-intercept form of the equation of the line that goes through (1,0).
